You pick up 20-newton book off the floor and put it on a shelf 2 meters high. How much work did you do

A bungee cord with a spring constant of 800 stretches 6 meters at its greatest displacement. How much elastic potential energy d

Vinil7 [7]

Elastic potential energy is given by formula

$U = \frac{1}{2} kx^2$

here we know that

$k = 800 N/m$

$x = 6 m$

Now using above formula we have

$U = \frac{1}{2}(800)(6^2)$

$U = 14400 J$

So elastic potential energy in the chord is 14400 J

4 0

3 years ago

A bicycle tire is spinning counterclockwise at 2.70 rad/s. During a time period Δt = 1.50 s, the tire is stopped and spun in the

Andru [333]

Answer:

Δω = -5.4 rad/s

αav = -3.6 rad/s²

Explanation:

Given:

Initial angular velocity = ωi = 2.70 rad/s

Final angular velocity = ωf = -2.70 rad/s (negative sign is

due to the movement in opposite direction)

Change in time period = Δt = 1.50 s

Required:

Change in angular velocity = Δω = ?

Average angular acceleration = αav = ?

Solution:

Angular velocity (Δω):

Δω = ωf - ωi

Δω = -2.70 - 2.70

Δω = -5.4 rad/s.

Average angular acceleration (αav):

αav = Δω/Δt

αav = -5.4/1.50

αav = -3.6 rad/s²

Since, the angular velocity is decreasing from 2.70 rad/s (in counter clockwise direction) to rest and then to -2.70 rad/s (in clockwise direction) so, the change in angular velocity is negative.

7 0

3 years ago

Read 2 more answers

Where do you see triangulation used on this structure? Explain how triangulation

Olegator [25]

I like your profile picture:)

3 0

3 years ago

an experiment is set up to measure the effect of a gasoline additive on fuel consumption rate. what would be the control in this

Tamiku [17]

The control setup in this experiment would be one tank that does not contain any of the additives. Since the tanks with the gasoline additives would need to be compared with a tank that is not affected by the results of these additives.

4 0

3 years ago

A 2.00 kg block hangs from a spring. A 300 g body hung below the block stretches the spring 2.00 cm farther. (a) What is the spr

Leokris [45]

The spring constant is 147 N/m

Given the mass of the block is 2.00 kg , the mass of the body is 300 g and the length of the spring is 2.00 cm

We need to find the spring constant

A spring is an object that can be deformed by a force and then return to its original shape after the force is removed.

The force required to stretch an elastic object such as a metal spring is directly proportional to the extension of the spring

We know that F = kx

300(9.8)= k (0.02)

k = 147.15 N/m

Rounding off to the nearest is 147N/m

The spring constant is 147N/m

Learn more about Hooke's law here

brainly.com/question/15365772

#SPJ4

7 0

2 years ago