The Lysosome is marked with an x
Answer:
Explanation:
Can you provide a picture? I can outline the reactions though. a) will make a Z double bond from a triple bond and then peroxyacid can do epoxidation. b) will make the Z double bond then ozonolysis to double bond will create to aldehyde compounds. c) is essentially useless unless there is a ketone or aldehyde in the compound already since H2/Pd will fully reduce the alkyne (which I am assuming is present) and so the peroxyacid can't do epoxidation and can only do baeyer villiger oxidation, and d) reduces the alkyne to an E alkene and then do epoxidation to give an epoxide (with trans steroechemistry)
The organelle that gives shape to the cell is call the cell wall
A)
Among the given compounds,
Methyl benzoate is less polar than Methyl nitrobenzoate. This is because
Methyl nitrobenzene contains an additional polar group (
-NO₂) which increases its polarity. Therefore, <span>Methyl benzoate having any additional polar group is less polar than Methyl nitrobenzoate.
B)
Below a developed
TLC is shown. It contain three spots. A spot at left (
blue) is for Methyl benzoate, the middle spot is of crude product (containing reactant and product) and the spot at right (
red) is for Methyl Nitrobenzoate. It is clearly shown that the Methyl benzoate being less polar has traveled more while Methyl nitrobenzoate being polar interacts with the stationary phase has traveled less. The middle spot shows the presence of both, reactant and product.</span><span>
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