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inysia [295]
4 years ago
9

A chloride of this element is 67.2% chlorine by mass. In a 100 g sample how many moles of chlorine are there? (This info will be

used to determine the empirical formula. Because the accuracy of the result in the last question for this set of questions depends on the accuracy of this answer, use the atomic mass of Cl accurate to 4 SIG. FIG.).
Chemistry
1 answer:
Ann [662]4 years ago
4 0

Answer:

1.896 mol Cl

Explanation:

  • Because the chloride is 67.2% chlorine by mass, i<u>n a 100 g sample of this compound, we would have 67.2 g of chlorine.</u>

With that information then we can calculate <u>the moles of chlorine</u> present in 67.2 g, using its atomic mass (accurate to 4 sig. fig. as the exercise asked):

67.2 g Cl ÷ 35.45 g/mol = 1.896 mol Cl

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Answer:

M_{per}= 52.86

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Explanation:

<u>First mixture</u>:

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m_{met1}=200 kg * 0.4= 80 kg

m_{wat1}=200 kg * 0.6= 120 kg

<u>Second mixture</u>:

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m_{wat2}=150 kg * 0.3= 45 kg

Final mixture:

m_{metF=80 kg + 105 kg= 185 kg

m_{watF}=120 kg + 45 = 165 kg

M_{per}=\frac{185 kg}{185 kg + 165 kg}*100= 52.86

W_{per}=\frac{165 kg}{185 kg + 165 kg}*100=47.14

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