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2 years ago

11

A car moves 20 km towards the North and then 35 km at an angle of 60o towards west of North. Its magnitude of displacement from

the initial position will be

1 answer:

Law Incorporation [45]2 years ago

8 0

Answer:

15

Explanation:

displacement = initial position - final position

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On Earth, the gravitational field strength is 10 N/kg. Calculate Ep for a 4 kg bowling ball have that is being held 2 m above th

Soloha48 [4]

Answer:

80 J

Explanation:

Ep = mgh

Ep = (4 kg) (10 m/s²) (2 m)

Ep = 80 J

4 0

3 years ago

Help me pls its for my science class i need to show my work

Lostsunrise [7]

Answer:

P = 5880 J

Explanation:

Given that,

The mass of the block, m = 30 kg

The block is sitting at a height of 20 m.

The block will have gravitational potential energy. The formula for gravitational potential energy is given by :

$P=mgh\\\\=30\times 9.8\times 20\\\\=5880\ J$

So, the required potential energy is equal to 5880 J.

6 0

2 years ago

A person throws a ball straight up. He releases the ball at a height of 1.75 m above the ground and with a velocity of 12.0 m/s.

Lyrx [107]

Answer:

a) 1.22 s

b) 9.089 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-12}{-9.81}\\\Rightarrow t=1.22\ s$

Time taken by the ball to reach the highest point is 1.22 seconds

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=12\times 1.22+\frac{1}{2}\times -9.81\times 1.22^2\\\Rightarrow s=7.339\ m$

The maximum height the ball will reach above the ground is 1.75+7.339 = 9.089 m

8 0

3 years ago

A rock is suspended by a light string. When the rock is in air, the tension in the string is 43.8 N . When the rock is totally i

sergeinik [125]

Answer:

Density of unknown liquid is $2047 kg/m^3$

Explanation:

When rock is suspended in air then the weight of the rock is counter balanced by the tension force in the string

So here we have

$T = mg = 43.8 N$

now when the rock is immersed in water then the tension in the string is and buoyancy force due to water is counter balanced by the weight of the object

so here we have

$T_1 + F_b = mg$

$31.3 + F_b = 43.8$

$F_b = 43.8 - 31.3 = 12.5 N$

now we have

$(1000)V(9.81) = 12.5$

$V = 1.27 \times 10^{-3} m^3$

now when the rock is immersed into other liquid then we have

$T_2 + F_b' = mg$

$18.3 + F_b' = 43.8$

$F_b' = 25.5 N$

now we have

$\rho(1.27 \times 10^{-3})(9.81) = 25.5$

$\rho = 2047 kg/m^3$

4 0

3 years ago

Dfine ' weight of moist air '

grandymaker [24]

Answer:

First of all, “moist air” is air with a high water vapor content. Water vapor, the invisible, gaseous form of water, occurs in highly variable amounts in the atmosphere. Water is composed of a hydrogen atom and two oxygen atoms (H2O) and has a molecular weight of 18 grams per mole.

6 0

2 years ago