Question

HELP FOR FINAL

Answer 1

Volume of CO₂ obtained : 13 L

Further explanation

Reaction

C₂H₅OH + 3 O₂ ⇒ 2 CO₂ + 3 H₂0 + 8842 Joules

moles of ethanol=0.28

From equation, mol ratio ethanol : CO₂ = 1 : 2, so mol CO₂ :

$\tt \dfrac{2}{1}\times 0.28=0.56$

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

Then volume of CO₂ :

$\tt V~CO_2=mol\times 22.4=0.56\times 22.4=12.544\approx 13~L$