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oksano4ka [1.4K]
3 years ago
6

What is it I need help​

Chemistry
1 answer:
dybincka [34]3 years ago
3 0
Hi, i think the correct answer would be D .
You might be interested in
Read the text
Citrus2011 [14]

Answer:

1. EXPOSE TWO GROUPS TO THE AROMA OF CHOCOLATE CHIP COOKIES BAKING

2.HAVE ONE GROUP EAT ONLY CHOCOLATE CHIPS COOKIES, AND HAVE THE OTHER GROUP EAT ONLY RADISHES

3.

3 0
2 years ago
Zinc and hydrochloric acid react to form zinc chloride and hydrogen gas according to
stealth61 [152]

Explanation:

Mole ratio of Zn to HCl = 1 : 2.

If we use all 2.0mol of Zn, we would need 2.0 * 2 = 4.0mol of HCl. However we only have 3.0mol of HCl.

Therefore HCl is limiting.

6 0
3 years ago
Ammonia can be produced in the laboratory by heating ammonium chloride
AnnyKZ [126]

Answer:

Mass = 2.89 g

Explanation:

Given data:

Mass of NH₄Cl = 8.939 g

Mass of Ca(OH)₂ = 7.48 g

Mass of ammonia produced = ?

Solution:

2NH₄Cl   +  Ca(OH)₂     →    CaCl₂ + 2NH₃ + 2H₂O

Number of moles of NH₄Cl:

Number of moles = mass/molar mass

Number of moles = 8.939 g / 53.5 g/mol

Number of moles = 0.17 mol

Number of moles of Ca(OH)₂ :

Number of moles = mass/molar mass

Number of moles = 7.48 g / 74.1 g/mol

Number of moles = 0.10 mol

Now we will compare the moles of ammonia with both reactant.

                      NH₄Cl          :          NH₃

                          2              :           2

                         0.17          :          0.17

                   Ca(OH)₂         :          NH₃

                        1                :           2

                    0.10              :          2/1×0.10 = 0.2 mol

Less number of moles of ammonia are produced by ammonium chloride it will act as limiting reactant.

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 0.17 mol × 17 g/mol

Mass = 2.89 g

6 0
2 years ago
How did Mendeleev arrange the known elements?
Agata [3.3K]
In order of relative atomic mass.
4 0
3 years ago
Read 2 more answers
Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these
deff fn [24]
The formation of nitric acid from nitrogen, hydrogen, and oxygen can be written as,

     N₂ + H₂ + 3O₂ --> 2HNO₃

The net enthalpy of formation of nitric acid is calculated by,
   Hrxn = Hproduct - Hreactant

Since all the reactants are in their elemental forms, the simplified equation would be,

    Hrxn = Hproduct 

Substituting,

    Hrxn = (-186.81 kJ/mol)(2 mols)

<em>Answer: -372.42 kJ</em>

7 0
3 years ago
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