Completed question:
In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?
Answer:
0.557
Step-by-step explanation:
For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:
0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443
Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:
1 - 0.443
0.557
Answer:
$1800 at 9% and $1000 at 6%
Step-by-step explanation:
Not needed
The answer i think is it c
Answer:
1.
-2 = x/4 + 1
Subtract 1 from both sides:
-2 - 1 = x/4 + 1 - 1
-3 = x/4
Multiply both sides by 4:
-3 * 4 = x/4 * 4
-12 = x
2.
3x+5
3.
X= 12 or 18
This could be read two different ways.
0=2/3x-12
12=2/3x
12÷2/3=x
12*3/2=x
18=x
—-OR—-
0=2/3(x-12)
0=2/3x-8
8=2/3x
8÷2/3=x
8*3/2=x
12=x
Answer:
6.
Step-by-step explanation:
|2y-2| when y = 2
= |2(-2)-2|
= |-4 - 2|
= |-6|
= 6.
