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expeople1 [14]
3 years ago
14

True or false: Only liquids can be described as fluids. I NEEED HELPP NOWWW

Chemistry
1 answer:
zavuch27 [327]3 years ago
6 0

Answer:

Explanation:

no, as it can also be used to describe a gas- a fluid includes liquids, gases and plasms

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calculate the number of moles of sulfuric acid that is contained in 250 mL of 8.500 M sulfuric acid solution
san4es73 [151]

Answer : The moles of H_2SO_4 are, 2.125 mole.

Explanation : Given,

Molarity of H_2SO_4 = 8.500 M

Volume of solution = 250 mL  = 0.250 L    (1 L = 1000 mL)

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Moles of }H_2SO_4}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

8.500M=\frac{\text{Moles of }H_2SO_4}{0.250L}

\text{Moles of }H_2SO_4=2.125mol

Therefore, the moles of H_2SO_4 are, 2.125 mole.

5 0
3 years ago
The molecular mass of methyl ethanoate is 75.1 amu . calculate the molecular mass of propanoic acid, an isomer of methyl ethanoa
iren [92.7K]
Molecular Formula of Propanoic Acid is....

                                                C₃H₆O₂
Where;

Atomic Mass of C  =  12

Atomic Mass of H  =  1

Atomic Mass of O  =  6

Substituting Atomic Masses in molecular formula,

                                                (12)₃ + (1)₆ + (16)₂

                                                   36  +  6  +  32

                                                        74 g/mol

Result:
            
Molecular Mass of Propanoic Acid is 74 g/mol. Structure of Methyl Ethanoate and Propanoic Acid are as follow,

7 0
3 years ago
Using the solubility graph place the substances in order from most soluble (#1) to least soluble at 40°C. KNO3, NaClO3,KBr, NaCl
mestny [16]

Answer:

  • NaClO₃ > KBr > KNO₃ > NaCl.

Explanation:

The attached file contains the graph with the solubility curves for the four substances, KNO₃, NaClO₃, KBr, NaCl.

To determine the solubility of each salt at a certain temperature, you read the temperature on the horizontal axis, labeled Temperature (ºC), and move upward up to intersecting the curve of the corresponding salt. Then, move horizontally up to insersceting the vertical axis, labeled Solubility (g/100g of H₂O), to read the solubility.

The higher the reading on the vertical axis, the higher the solubility.

The red vertical line that I added is at a temperature of 40ºC.

The number in blue indicate the order in which the solubility curves are intersected at that temperature:

  • 4: NaCl: this is the lowest solubility
  • 3: KNO₃: this is the second lowest solubility
  • 2: KBr: this is the third lowest solubility
  • 1: NaClO₃: this is the highest solubility.

Thus, the rank, from most soluble to least soluble is:

  • NaClO₃ > KBr > KNO₃ > NaCl.

7 0
3 years ago
Calculate the mass of Octane needed to release 6.20 mol Co2
n200080 [17]
The combustion reaction of octane is as follow,

                           C₈H₁₈  +  25/2 O₂     →     8 CO₂  +  9 H₂O

According to balance equation,

8 moles of CO₂ are released when  =  114.23 g (1 mole) Octane is reacted

So,

      6.20 moles of CO₂ will release when  =  X g of Octane is reacted

Solving for X,
                                     X  =  (114.23 g × 6.20 mol) ÷ 8 mol

                                     X  =  88.52 g of Octane
Result:
           88.52 g of Octane is needed to release 6.20 mol CO₂.
8 0
3 years ago
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Mrac [35]
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3 years ago
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