Answer:
28g
Explanation:
Given parameters:
Number of moles of hydrogen = 3moles
Unknown:
Mass of nitrogen used = ?
Solution:
To solve this problem, let us establish the balanced reaction equation first;
N₂ + 3H₂ → 2NH₃
From the balanced reaction equation;
3 mole of H₂ will combine with 1 mole of N₂
Now,
Mass of Nitrogen = number of moles x molar mass
Molar mass of N₂ = 2(14) = 28g/mol
Mass of Nitrogen = 1 mole x 28g/mole = 28g
I believe your answer is Favorable.
Hope this helps, and happy studying~!
~{Dunsforhands}
The ph is always greater than 7
<u>Answer:</u> The expression for equilibrium constant in terms of concentration is ![K_c=[CO_2]](https://tex.z-dn.net/?f=K_c%3D%5BCO_2%5D)
<u>Explanation:</u>
Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric coefficients. It is represented by 
For a general chemical reaction:

The
is written as:
![K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D)
The concentration of pure solids and pure liquids are taken as 1.
For the given chemical reaction:

The expression for
is:
![K_{c}=\frac{[MgO][CO_2]}{[MgCO_3]}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BMgO%5D%5BCO_2%5D%7D%7B%5BMgCO_3%5D%7D)
In the above expression, magnesium oxide and magnesium carbonate will not appear because they are present in solid state.
So, the expression for
becomes:
![K_{c}=[CO_2]](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5BCO_2%5D)
Hence, the equilibrium constant for the reaction is given above.