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Ivanshal [37]
3 years ago
9

Physical properties are the characteristics of matter that can be seen or measured through direct observation.

Chemistry
1 answer:
navik [9.2K]3 years ago
8 0
Physical properties are the characteristics of matter that can be seen or measured through direct observation.
It is true
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4 years ago
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Please help 15 points
Rus_ich [418]

Nitrogen gained 4 electrons.

Because Nitrogen's redox number went from +6 to +2, it must have gained 4 electrons (-4) in order to achieve this number. Thus, Nitrogen is reduced.

4 0
3 years ago
Upon combustion, a compound containing only carbon and hydrogen produces 2.67 g<img src="https://tex.z-dn.net/?f=CO_%7B2%7D" id=
Hoochie [10]

Answer:

\boxed{\text{CH$_{2}$}}

Explanation:

1. Calculate the mass of each element

\text{Mass of C} = \text{2.67 g } \text{CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{0.7286 g C}\\\\\text{Mass of H} = \text{1.10 g }\text{H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g } \text{{H$_{2}$O}}} = \text{0.1231 g H}

2. Calculate the moles of each element

\text{Moles of C = 0.7286 g C}\times\dfrac{\text{1 mol C}}{\text{12.01 g C }} = \text{0.060 67 mol C}\\\\\text{Moles of H = 0.1231 g H} \times \dfrac{\text{1 mol H}}{\text{1.008 g H}} = \text{0.1221 mol H}

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

\text{C: } \dfrac{0.06067}{0.06067}= 1\\\\\text{H: } \dfrac{0.1221}{0.06067} = 2.015

4. Round the ratios to the nearest integer

C:H = 1:2

5. Write the empirical formula

The empirical formula is \boxed{\text{CH$_{2}$}}

8 0
3 years ago
Use VSEPR theory to predict the bond angles in a molecule of methane (CH4), which is a covalently bonded molecule.
coldgirl [10]

Answer:

109.5 Degrees

Explanation:

Because CH4 is sp4 hybridized (Carbon is bonded to the 4 Hydrogens), the geometry of the molecule must be tetrahedral. Tetrahedral moleculues have bond angles of 109.5 Degrees.

6 0
3 years ago
The reaction A + B → 2 C has the rate law rate = k[A][B]³. By what factor does the rate of reaction increase when [A] remains co
lawyer [7]

Answer:

8

Explanation:

To solve this question, we just need to put the new number into the equation. If [A] remain constant then that mean [A2]= [A1]. If B doubled, then that mean [B2]= 2[B2]. To find what factor does the rate of reaction increases, we need to divide the first reaction rate with the second. The calculation will be:

rate2/rate1= k[A2][B2]³     /     k[A1][B1]³

rate2/rate1= [A1][2B1]³      /     [A1][B1]³

rate2/rate1=  A1*8B1³       /     A1*B1³

rate2/rate1= 8/1= 8

The rate of reaction will be 8 times faster.

7 0
3 years ago
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