Answer:
Empirical formula is C₉H₁₅O
Molecular formula = C₈₁H₁₃₅O
₉
Explanation:
Percentage of carbon = 77.60%
Percentage of oxygen = 11.45%
Percentage of hydrogen = 10.95%
Molecular weight = 1253 g/mol
Molecular formula = ?
Empirical formula = ?
Solution:
Number of gram atoms of C = 77.60 g /12g/mol =6.5
Number of gram atoms of O = 11.45 g / 16 g/mol = 0.72
Number of gram atoms of H = 10.95 g / 1.008 g/mol= 10.9
Atomic ratio:
C : H : O
6.5/0.72 : 10.9/0.72 : 0.72/0.72
9 : 15 : 1
C : H : O = 9 : 15 : 1
Empirical formula is C₉H₁₅O
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
n = 1253 / 139
n = 9
Molecular formula = n (empirical formula)
Molecular formula = 9 (C₉H₁₅O
)
Molecular formula = C₈₁H₁₃₅O
₉
