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inessss [21]
3 years ago
10

Rashid can do a piece of work in 8 days, which Tipu can finish in 12 days. If they work at it on alternate days with Rashid begi

nning, in how many days, the work will be finished?
Mathematics
1 answer:
algol [13]3 years ago
3 0

Answer:

The work will be finished in 10 days.

Step-by-step explanation:

Rashid can do a piece of work in 8 days

This means that each day he works, Rashid does \frac{1}{8} of the work.

Tipu can finish in 12 days.

This means that each day he works, Tipu does \frac{1}{12} of the work.

Each 2 days:

Each 2 days they work, the amount done is given by:

\frac{1}{8} + \frac{1}{12} = \frac{3 + 2}{24} = \frac{5}{24}

Each 2 days, 5/24 of the work is done:

The number of periods of 2 days that is needed to finish the work(100% = 1 completed), is given by:

d = \frac{1}{\frac{5}{24}} = \frac{24}{5} = 4.8

2*4.8 = 9.6

Rounding up

The work will be finished in 10 days.

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A stock has had returns of 7 percent, 25 percent, 17 percent, −13 percent, 25 percent, and −6 percent over the last six years. W
Tems11 [23]

Answer: Geometric average return would be 0.10% and arithmetic average return would be 9.17%.

Step-by-step explanation:

Since we have given that

Returns are as follows:

7%, 25%, 175, -13%, 25% and -6%.

Geometric return is given by

\sqrt[6]{(1+0.07)(1+0.25)(1+0.17)(1-0.13)(1+0.25)(1-0.06)}-1\\\\=\sqrt[6]{(1.17)(1.25)(1.17)(0.87)(1.25)(0.94)}-1\\\\=0.097\%=0.10\%

Arithmetic average return would be

\dfrac{7+25+17-13+25-6}{6}=9.17\%

Hence, geometric average return would be 0.10% and arithmetic average return would be 9.17%.

7 0
3 years ago
Which of the following statements about JK and JL is true?
mash [69]

Answer:

B. JK is longer than JL

Step-by-step explanation:

JK is 6, JL is 5. Therefore, JK is longer than JL.

8 0
2 years ago
Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x
Stolb23 [73]

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

y=a(x-h)^2+k  

(where (h, k) is the vertex)

Given:

  • vertex = (1, -108)

\implies y=a(x-1)^2-108

Given:

  • y-intercept = (0, -105)

\implies a(0-1)^2-108=-105

\implies a(-1)^2=-105+108

\implies a=3

Therefore:

\implies y=3(x-1)^2-108

The x-intercepts are when y = 0

\implies 3(x-1)^2-108=0

\implies 3(x-1)^2=108

\implies (x-1)^2=36

\implies x-1=\pm \sqrt{36}

\implies x=1\pm 6

\implies x=7, x=-5

Therefore, the x-intercepts are (7, 0) and (-5, 0)

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2 years ago
Dad gave Tyler and Emily the same amount of pocket money Emily bought a t shirt for $41 and she had $6 left how much money did d
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Answer:

Dad gave Tyler $47.

Step-by-step explanation:

You add the money that Emily had left and the cost of the t-shirt.

41+6= 17

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