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Hunter-Best [27]
4 years ago
6

What is the length of segment QR? (Show all work)

Mathematics
1 answer:
vazorg [7]4 years ago
3 0
So if QR and PQ are the same ( which they are bc the angles and other sides are the same) 3n-1= 5n-7 so -1= 2n -7 so 6 = 2n so n = 3 then QR is 5n -7 so 5 x 3 is 15-7 is 8 so the answer is 8. Hope this helps :)
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Answer:

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4 years ago
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Read 2 more answers
Find the derivative of the following functions: a. f(x) = (x^3 + 5)^1/4 - 15e^x^3 b. f(x) = (x - 3)^2 (x - 5)/(x - 4)^2(x^2 + 3)
Darya [45]

Answer:

Step-by-step explanation:

Given function is

(a)F(x)=\left ( x^{3}+5\right )^{0.25}-15e^{x^{3}}

F^{'}\left ( x\right )=0.25\left ( x^{3}+5\right )^{-0.75}\frac{\mathrm{d} x^{3}}{\mathrm{d} x}-15e^{x^{3}}\frac{\mathrm{d} x^{3}}{\mathrm{d} x}

F^{'}\left ( x\right )=0.25\left ( x^{3}+5\right )^{-0.75}\times 3x^{2}-15e^{x^{3}}\times \left ( 3x^{2}\right )

(b)F(x)=\frac{\left ( x-3\right )^2\left ( x-5\right )}{\left ( x-4\right )^2\left ( x^{2}+3\right )^5}

F^{'}\left ( x\right )=\frac{\left [ 2\left ( x-3\right )\right \left ( x-5\right )+\left ( x-3\right )^2]\left [ \left ( x-4\right )^2\left ( x^2+3\right )^5\right ]-\left [ 2\left ( x-4\right )^{3}\left ( x^2+3\right )^5+5\left ( x^2+3\right )^4\left ( 2x\right )\left ( x-4\right )^2\right ]\left [ \left ( x-3\right )^2\left ( x-5\right )\right ]}{\left [\left ( x-4\right )^2\left ( x^2+3\right )^5\right ]^2}

6 0
4 years ago
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