The consecutive positive integers would be: x and (x+1),
We would have to solve the following equation to find these numbers:
x(x+1)-[x+(x+1)]=29
x²+x-2x-1=29
x²-x-30=0
x=[1⁺₋√(1+120)]/2
x=(1⁺₋11)/2
We have two possible solutions:
x₁=(1-11)/2=-5 then: (x+1)=-5+1=-4 This is not the solution.
x₂=(1+11)/2=6 then: (x+1)=6+1=7 This solution is right.
Answer: the numbers would be 6 and 7.
Answer:
Step-by-step explanation:
Without the variable x, your "f(x) = 3(18)*" is not a function. If you meant
f(x) = 3(18)^x, then the domain is "the set of all real numbers," and the range is (0, infinity).
the initial value is 3: f(0) = 3(18)^0 = 3(1) = 3
Answer: 8 weeks
Step-by-step explanation:
Answer:
Hi
Step-by-step explanation:
answer is B
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