Answer:
Bella can complete work alone in 120 minutes
Step-by-step explanation:
Ana and Bella together can complete the shoveling in 30 minutes.
They can do a part of work in 1 minute = 
Ana can do work alone in 40 minutes
She can do part of work in 1 minute = 
So, Bella can do a part of work in 1 minute = 
= 
Bella can do
part of work in 1 minute
Bella can do whole work in minutes = 120
Hence Bella can complete work alone in 120 minutes
Answer:
Step-by-step explanation:
y + 2 = -3(x - 0)
y + 2 = -3x + 0
y = -3x - 2
solution is 1
Answer:
Step-by-step explanation:
- A) x⁶ + 27y⁹ = (x²)³ + (3y³)³ - sum of cubes
- B) 3x⁹ - 64y³ - the first term is not a cube
- C) 27x¹⁵ - 9y³ - the second term is not a cube
- D) 125x²¹- 64y³ = (5x⁷)³ - (4y)³ - difference of cubes
Correct option is the last one
If you take 3.5 and divide it by 0.05, or times 20, that would make it 70.

The equation of circle in standard form can be represented as :

where,
- h = x - coordinate of centre = 0
- k = y - coordinate of centre = 0
- r = radius of circle = 6 units
now, let's plug in the values :


That's the required equation of circle.