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Triss [41]
3 years ago
11

Decipher this puzzle SECRET SECRET SECRET

Chemistry
2 answers:
Nady [450]3 years ago
5 0

Answer:

Top secret

Explanation:

Top secret because it is circling the word secret on the stack of three so its the secret on the top. It's a play on words or words riddle.

Olin [163]3 years ago
3 0
The answer is top secret
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The correct value according to Ruler A is 2.2 cm
vladimir2022 [97]

Answer:

Measure the diameter of the circle using Ruler A and Ruler B.

Given that the actual diameter of the circle is 2.264 cm, classify the following statements that describe the diameter measurement of the circle according to the ruler.

Drag the appropriate items to their respective bins.

3 0
3 years ago
Write the step by step process of digestion in ruminants using 4 square method.
Vaselesa [24]

The digestion process in Ruminants begins by chewing and swallowing their food.

<h3>What are ruminants?</h3>

A ruminant is any herbivorous animal that has a stomach with four compartments, which are tasked with acquiring nutrients from plant-based food by fermenting it prior to digestion.

The digestion process in Ruminants begins by chewing and swallowing their food. Ruminants do not completely chew the food they eat, but just consume or gulp as much they can and then swallow the food. This is actually an adaptation by which these animals have evolved to spend as little time as possible feeding so that they are not hunted down by any predators while they are eating.

As mentioned earlier, the stomach of these Ruminants is divided into 4 chambers – rumen, reticulum, omasum, and the abomasum.

The process of digestion begins with the first two chambers of the stomach, the rumen and reticulum by softening the ingested matter. Later the microbes present in the rumen produces the cellulase enzymes required to digest the cellulose.

Once the plant fibres have been broken down to provide vitamins, proteins, and other organic acids, the nutrients are absorbed into the animal’s bloodstream.

Coarse plants are sent further into the next chamber for further digestion. Here is where the further bacterial action takes place and the food is formed into soft chunks called the cud.

This cud produced is regurgitated back into the animal’s mouth where it can be chewed again. The saliva of the cow greatly aids in digesting the cud.

After chewing, the food bypasses the two chambers of the stomach and directly enters the third chamber. The walls of the third chamber mash and compact the food molecules further, and then pass it to the fourth chamber – the abomasum.

The final digestion in the stomach is carried by the abomasum and then passed to the intestine.

Learn more about the ruminants here:

brainly.com/question/26752412

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3 0
2 years ago
Solve The Combined Gas Law Problem
Ad libitum [116K]

Answer:

200 torr

Explanation:

because it have 250ml when we subtract the 50 we get answer

8 0
2 years ago
DH
viva [34]

a. 4- bromocyclohexanol is an acidic proton

b. Benzenesulfonic acid deactivates the entire process

c. (2S, 3R)-2,3-Dibromobutane are racemic mixtures

d.  Williamson synthesis cannot be used with tertiary alkyl halides

e. Nucleophiles are not involved in the rate determining step

<h3>The reasons that might help to explain the following observations are:</h3>

a. Grignard reagents cannot be made if acidic functional groups are also present in the halogen compound and it is also destroyed by reaction with acidic hydrogen atoms of water, alcohols, phenols, or carboxylic acid groups.

4-bromocyclohexanol is an acidic proton compound

b. Benzenesulfonic acid does not undergo Friedel-Crafts alkylation because the carboxylic group causes deactivation, carboxylic group and the Lewis acid catalyst are also bonded in the process.

c. (2S, 3R)-2,3-Dibromobutane has a specific rotation, [a]o, of 0° are racemic mixtures having equal and opposite specific rotations and a racemic mixture has a specific rotation of zero (0°)

d. This is because the Williamson synthesis cannot be used with tertiary alkyl halides which in this case is t-butyl bromide because they undergo elimination reactions instead of participating in SN2 reactions and form alkenes instead of ethers.

e. Doubling the concentration of a nucleophile has no effect on the rate of a substitution reaction because the nucleophile is not involved in the rate-determining step of the SN-1 reaction.

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5 0
3 years ago
Draw the major organic product for the reaction of 1-phenylpropan-1-one with the provided phosphonium ylide.
prohojiy [21]

Answer:

2-methylene propylbenzene

Explanation:

The Wittig Reaction is a reaction that converts aldehydes and ketones into alkenes through reaction with a phosphorus ylide.

The ketone in this case is 1-phenylpropan-1-one. The provided phosphonium ylide is shown in the image attached. The reaction involves;

i) alkylation  

ii) addition

The product of the major organic product of the reaction is 2-methylene propylbenzene.

4 0
3 years ago
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