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MA_775_DIABLO [31]
3 years ago
7

Can someone tell me the acceleration?

Physics
1 answer:
maw [93]3 years ago
5 0
Acceleration is the speed of an object speeding up
Whether it is velocity or just speed
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In which direction does a bag at rest move when a force of 20 newton's is applied from the right?
Olegator [25]

The bag moves to the left.

This is because of Newton's third law of motion that states:

For every action force on a body, there is an opposite and equal reaction force.

Thus pushing the bag from the right makes it move to the left.


8 0
4 years ago
The impact that an earthquake can have on an area?
tatyana61 [14]

Answer:

The primary effects of earthquakes are ground shaking, ground rupture, landslides, tsunamis, and liquefaction. Fires are probably the single most important secondary effect of earthquakes.

Explanation:

7 0
3 years ago
Read 2 more answers
Which nucleus completes the following equation?
melomori [17]

The nucleus that completes the equation given above is 218/85 At, which is option D.

<h3>What is a nuclear fission?</h3>

Nuclear fission is a nuclear reaction in which a large nucleus splits into smaller ones with the simultaneous release of energy.

According to this question, the following nuclear fission reaction is given: 222/87Fr = 4/2He+ ?

To find the missing nucleus, we subtract 4 from 222 to get 218, therefore, the nucleus that completes the equation given above is 218/85 At.

Learn more about nuclear fission at: brainly.com/question/913303

#SPJ1

4 0
2 years ago
A 4,000 kg truck is moving at +10 m/s hits a 1500 kg parked car which moves off at +10 m/s. What is the velocity of the truck
Igoryamba

Answer:

10m/s

Explanation:

Using the law of conservation of momentums

M1u1+m2u2 = (m1+m2)v

Substitute.

4000(10)+1500(10) = (4000+1500)v

40,000+15,000 = 5,500v

55000 = 5500v

v = 55000/5500

v= 10m/s

Hence the velocity of the truck after Collision is 10m/s

6 0
3 years ago
An ideal horizontal spring-mass system has a mass of 1.0 kg and a spring with constant 78 N/m. It oscillates with a period of 0.
steposvetlana [31]

Answer:

T = 0.71 seconds

Explanation:

Given data:

mass m = 1Kg, spring constant K = 78 N/m, time period of oscillation T = 0.71 seconds.

We have to calculate time period when this same spring-mass system oscillates vertically.

As we know

T = 2\pi \sqrt{\frac{m}{K} }

This relation of time period is true under every orientation of the spring-mass system, whether horizontal, vertical, angled or inclined. Therefore, time period of the same spring-mass system oscillating  vertically too remains the same.

Therefore, T = 0.71 seconds

6 0
3 years ago
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