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qwelly [4]
2 years ago
9

When you push an object, it pushes back with an equal and opposite force

Physics
1 answer:
Ksju [112]2 years ago
5 0

Answer:

I would say false

Explanation:

Because friction slows it down which means when the object bounces back it will not have the same energy or force that was applied before.

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In Millikan's oil drop experiment an oil drop is at rest between two large plates separated by 1.3 cm when the potential differe
sweet-ann [11.9K]

Answer:

Mass of the oil drop, m=3.01\times 10^{-15}\ kg

Explanation:

Potential difference between the plates, V = 400 V

Separation between plates, d = 1.3 cm = 0.013 m

If the charge carried by the oil drop is that of six electrons, we need to find the mass of the oil drop. It can be calculated by equation electric force and the gravitational force as :

qE=mg

m=\dfrac{qE}{g}

q=6e, e is the charge on electron

E is the electric field, E=\dfrac{V}{d}=\dfrac{400}{0.013}=30769.23\ V/m

m=\dfrac{6\times 1.6\times 10^{-19}\times 30769.23}{9.8}

m=3.01\times 10^{-15}\ kg

So, the mass of the oil drop is 3.01\times 10^{-15}\ kg. Hence, this is the required solution.

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3 years ago
What type of issue does the effects manufacturer need
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Answer:

A) Availability

Explanation:

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3 years ago
Both independent and dependent clauses
Assoli18 [71]

Answer: have a subject and a verb

Explanation:

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3 years ago
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3 years ago
Two capacitors, a 15 micro F and a 25 micro F, are connected in parallel to a 60 Hz source. The total capacitive reactance is :_
Stells [14]

Answer:

<em> 3980.89 ohms</em>

Explanation:

The capacitive reactance is expressed as;

X_c = \frac{1}{2 \pi fC}

f is the frequency

C is the capacitance of the capacitor

Given

f = 60H

C = C1+C2 (parallel connection)

C = 15μF + 25μF

C = 40μF

C = 40 * 10^{-6}F

Substitute into the formula:

X_c = \frac{1}{2(3.14)*60*40*10^{-6}}\\X_c =  \frac{1}{0.0002512}\\X_c = 3,980.89

<em>Hence the  total capacitive reactance is 3980.89 ohms</em>

5 0
3 years ago
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