Answer: Option (c) is the correct answer
Explanation:
It is known that when a neutral object comes in contact with a charged object then an opposite charge develops on the neutral object. But this development of charge occurs only when both the objects come in contact and if they are not in contact with each other then there occurs no charge on the neutral object.
As in the given situation, negatively-charged glass rod is brought near, but does not touch the sphere. So, there will occur no charge on the sphere.
Thus, we can conclude that final charge on the sphere is neutral.
Answer:
(iii) 6
Explanation:
Part a)
Since it is given that both ends are fixed and it is vibrating in 5th harmonic
So here it will have 5 number of loops in it
so we can draw it in following way
each loop will have 1 antinode and two nodes which means number of nodes is one more than number of anti-nodes
So there are 5 loops which means it will have 5 antinodes
and hence there will be 6 nodes in it
so correct answer will be
(iii) 6
Answer:
answer is number (a) If the car is moving on a straight road....
Explanation:
The distance moved and magnitude of displacement are equal only in the case of motion along a straight line. Because displacement is the shortest path between initial and find path. So, for car moving on straight road, distance moved and magnitude of displacement are equal.
Use the formula: <span><span><span><span>P1</span><span>V1</span></span><span>T1</span></span>=<span><span><span>P2</span><span>V2</span></span><span>T2</span></span></span>
We know that we want <span><span>P1</span>=<span>P2</span></span> so the pressure will remain constant, so we can say that: <span><span><span><span>P1</span><span>V1</span></span><span>T1</span></span>=<span><span><span>P1</span><span>V2</span></span><span>T2</span></span></span>
Plug in the values we know: <span><span><span><span>P1</span>⋅0.250L</span><span>283K</span></span>=<span><span><span>P1</span>⋅0.285L</span><span>T2</span></span></span>
(Remember that temperature must be done in Kelvin.)
Cross multiply: <span><span>T2</span>⋅<span>P1</span>⋅0.250L=283K⋅<span>P1</span>⋅0.285L</span>
Divide both sides by <span>P1</span>.
<span><span>T2</span>⋅0.250L=283K⋅0.285L</span>
<span><span>T2</span>=<span><span>283K⋅0.285L</span><span>0.250L</span></span></span>
<span><span>T2</span>=323K</span>
(This is also <span>50˚C</span>.)
