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icang [17]
2 years ago
15

A diploid somatic ("body") cell has 2n = 20 chromosomes. At the end of mitosis, each daughter cell would have ______ chromosomes

. At the end of meiosis I, each daughter cell would have ______ chromosomes. At the end of meiosis II, each daughter cell would have ______ chromosomes.
Chemistry
1 answer:
kozerog [31]2 years ago
7 0

Answer:

At the end of mitosis, 2n = 20

At the end of meiosis I, n = 10

At the end of meiosis II, n = 10

Explanation:

Mitosis is a type of cell division in which daughter cell produced are genetically identical to their mother cell. So, no. of chromosome does not change after mitosis.

So, at the end of mitosis, each daughter cell would have <u>20</u> chromosome.

Meiosis is a type of cell division in which mother cell produces two haploid cells ones with a single set of chromosomes.

Meiosis is a two step cell division, Meiosis I and Meiosis II.

In meiosis I, homologous pair separates, so no. of chromosomes becomes half.

In meiosis II, sister chromatids separates. So, the number of chromosomes remains same (i.e. Have same no. of chromosome as present in cell produced after meiosis I).

So, at the end of mitosis, each daughter cell would have <u>20</u> chromosome.

At the end of meiosis I, each daughter cell would have n = 10 chromosomes. At the end of meiosis II, each daughter cell would have n = 10 chromosomes.

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Which of the following would not be an isotope of carbon-12? A. Carbon-14 B. Carbon-13 C. Boron-12 D. Carbon-11
Oliga [24]
C because it isn't carbon
6 0
2 years ago
Rozwiaz logogryf. Z wyróżnionych pól odczytaj hasło i je zapisz.
saul85 [17]

Answer:

1) Nitrogen

2) Methane

3) Dipeptide

4) Ammonia

5) Glycine

In Polish/Po polsku

1) Azot

2) metan

3) dipeptyd

4) Amoniak

5) glicyna

Explanation:

English Translation

Solve logogriffs. Read the password from the highlighted fields and write it down.

1.The chemical element being the main component of air (it occupies 78% of its volume),

2. The simplest saturated hydrocarbon,

3. Is a result of combining two amino acid molecules,

4. Gas with a pungent odor, soluble in water; hydrogen and nitrogen synthesis product.

5. Common name of aminoacetic acid

(the first has four boxes, the second has five boxes, the third has eight quarters has seven, fifths and seven).

Thank you in advance

1) The main component of air that makes up 78% of the air is Nitrogen.

2) The simplest saturated hydrocarbon is the first member of the alkane family, Methane.

3) Two amino acids combine by forming peptide bonds between the carboxyl group of one amino acid and the amino group of another through dehydration synthesis (loss of 1 molecule of water). Hence, the result of the combination of two amino acids are called Dipeptides.

4) Nitrogen and Hydrogen come together to form only one known water soluble gas with pungent smell, called Ammonia.

5) Aminoacetic acid as its name suggests is an amino acid with the acetyl group. It is the simplest amino acid. The common name for this compound is Glycine.

In Polish/Po polsku

1) Głównym składnikiem powietrza, które stanowi 78% powietrza, jest azot.

2) Najprostszym nasyconym węglowodorem jest pierwszy członek rodziny alkanów, metan.

3) Dwa aminokwasy łączą się, tworząc wiązania peptydowe między grupą karboksylową jednego aminokwasu i grupą aminową innego przez syntezę odwodnienia (utrata 1 cząsteczki wody). Stąd wynik połączenia dwóch aminokwasów nazywa się dipeptydami.

4) Azot i wodór tworzą razem jeden znany gaz rozpuszczalny w wodzie o ostrym zapachu, zwany amoniakiem.

5) Kwas aminooctowy, jak sama nazwa wskazuje, jest aminokwasem z grupą acetylową. To najprostszy aminokwas. Powszechna nazwa tego związku to glicyna.

Hope this Helps!!!

Mam nadzieję że to pomoże!!!

8 0
2 years ago
Which expression is equivalent to 6m + (m - 2)(m + 7) + 3?
dedylja [7]
It’s is m2 +11m-11
I believe that’s right
8 0
3 years ago
Which pair shares the same empirical formula?
ZanzabumX [31]

Answer:- 3. CH_3 and C_2H_6

Explanations:- An empirical formula is the simplest whole number ratio of atoms of each element present in the molecule/compound.

For example, the molecular formula of benzene is C_6H_6 . The ratio of C to H in it is 6:6 that could be simplified to 1:1. So, an empirical formula of benzene is CH.

In the first pair, the ratio of C to H in first molecule is 2:4 that could be simplified to 1:2 and  the empirical formula is CH_2 . In second molecule the ratio of C to H is 6:6 and it could be simplified to 1:1. and the empirical formula is CH. Empirical formulas are different for both the molecules of first pair and so it is not the right choice.

In second pair, C to H ratio in first molecule is 1:2, so the empirical formula is CH_2 . The C to H ratio for second molecule is 1:4, so the empirical formula is CH_4 . Here also, the empirical formulas are not same and hence it is also not the right choice.

In third pair, C to H ratio in first molecule is 1:3, so the empirical formula is CH_3 . In second molecule the C to H ratio is 2:6 and it is simplified to 1:3. So, the empirical formula for this one is also CH_3 . Hence. this is the correct choice.

In fourth pair, first molecule empirical formula is CH. Second molecule has 2:4 that is 1:2 mole ratio of C to H and so its empirical formula is CH_2 . As the empirical formulas are different, it is not the right choice.

So, the only and only correct pair is the third one. 3. CH_3 and C_2H_6

4 0
3 years ago
Read 2 more answers
What volume is used to calculate the volume of a solid object ​
Degger [83]

Answer:

cubic measurements

Explanation:

i.e. cubic meter or cubic centimeter

3 0
3 years ago
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