HURRY!!!!
2 answers:
Answer:
2. decreasing the distance of the space shuttle from Earth
Explanation:
To increase the gravitational force on a space shuttle, it is a good thing to decrease the distance of the space shuttle from the earth.
This is based on the Newton's law of universal gravitation which states that "the gravitational force between two bodies is a directly proportional to the product of their masses and inversely proportional to the square of the distance between them".
Mathematically;
F =
G is the universal gravitation constant, it cannot be changed
m is the mass of the body
r is the distance
Since the distance is inversely proportional, is we reduce it, the value of the gravitational force will increase.
You might be interested in
Answer:
a) I= I₀ (cos²θ - cos⁴θ) b) 75.5º
Explanation:
a) For this exercise we must use Malus's law
I = I₀ cos² θ
where tea is the angle between the two polarizers.
We apply this expression to our case
* Polarizer 1 suppose that it is vertical and polarizer 2 (intermediate) is at an angle θ with respect to the vertical
I₁ = I₀ cos² θ
* We analyze for the polarity 2 and the last polarizer 3 which indicate that it must be at 90º from the first one, therefore it must be horizontal.
The angle of polarizers 2 and 3 is θ' measured from the horizontal, if we measure with respect to the vertical
θ₂ = 90- θ’ = θ
fiate that in the exercise we must take a reference system and measure everything with respect to this system.
I = I₁ cos² θ'
we substitute
I = (I₀ cos² tea) cos² (θ - 90)
cos (θ -90) = cos θ cos 90 + sin θ sin 90 = sin θ
I = Io cos² θ sin² θ
1= cos²θ+ sin²θ
sin²θ = 1 - cos²θ
I= I₀ (cos²θ - cos⁴θ)
b) to find when the intensity is maximum,
we can use that we have an extreme point when the drift is zero
= 0
\frac{dI}{d \theta}= Io (2 cos θ - 4 cos³θ) = 0
whereby
cos θ - 2 cos³ θ = 0
cos θ ( 1 - 2 cos² θ) = 0
The zeros of this function are in
θ = 90º
1-2cos²θ =0 cos θ = 0.25 θ = 75.5º
Let's analyze this two results for the angle of 90º the intnesidd is zero with respect to the first polarizer, so it is not an acceptable solution.
Consequently, the angle that allows the maximum intensity to pass is 75.5º
Answer:
Speed of river is 0.45 m/s
Speed of boat is 2.65 m/s
Explanation:
= Speed of river
= Speed of canoe
Adding the equations we get
Speed of river is 0.45 m/s
Speed of boat is 2.65 m/s