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3 years ago

9

A child accidentally drops a toy from his apartment window. It falls for 1.05 seconds. What is the velocity of the toy just befo

re it hits the ground?
How far does the toy fall during this time?

1 answer:

AVprozaik [17]3 years ago

6 0

Sorry!

This cannot be answered. We don't have weight, height, etc.

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Is Time and Light both connected in anyway?

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It is not connected by any way

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A measure of the disorder of a system is called

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Entropy is typically defined as either the level of randomness (or disorder) of a system or a measure of the energy dispersal of the molecules in the system.

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The escape velocity of any object from Earth is 11.2 km/s. (a) Express this speed in m/s and km/h. (b) At what temperature would

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Answer:

a ) 11.1 *10^3 m/s = 39.96 Km/h

b) T_{o2} =1.58*10^5 K

Explanation:

a) $v_{es} =v_{rms}$ = 11.1 km/s =11.1 *10^3 m/s = 39.96 Km/h

b)

M_O2 = 32.00 g/mol =32.0*10^{-3} kg/mol

gas constant R = 8.31 j/mol.K

$v_{rms} = \sqrt{ \frac{3RT}{M}}$

So, $v_{rms,o2} =\sqrt{ \frac{3RT_{o2}}{M_{o2}}}$

multiply each side by M_{o2}, so we have

$v_{rms,o2}^2 *M_{o2} =3RT_{o2}$

solving for temperature T_{o2}

$T_{o2} = \frac{v_{rms,o2}^2 *M_{o2}}{3R}$

In the question given, $v_{rms} =v_{es}$

$T_{o2} = \frac{(11.1*10^3)^2 *32.0*10^{-3}}{3*8.31}$

T_{o2} =1.58*10^5 K

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4 years ago

The wavelength of a wave is the horizontal distance from a ________ to an adjacent ________.

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Mars, which has a radius of 3.4 × 106 m and a mass of 6.4 × 1023 kg, orbits the Sun, which has a mass of 2.0 × 1030 kg at a dist

Elena L [17]

Answer:

Tangential speed of Mass revolution is greater

Explanation:

In the above question, we are given the following values:

Radius of Mars = 3.4 × 10^6 m

Mass of Mars = 6.4 × 10^23 kg

Mass of the sun = 2.0 × 10^30 kg at a distance of 2.3 × 10^11m.

Mar’s revolution around the sun = 687 days.

Time of Revolution = 24 hours and 37 minutes to complete one revolution.

Step 1

Find the tangential speed of rotation of Mars

Rotation of Mars = 2 × π × r

Radius of Mars = 3.4 × 10^6 m

Rotation of Mars = 2 × π × 3.4 × 10^6 m

Rotation of Mars = 21362830.044m

= 21.4 × 10^6 m

Tangential Speed of rotation for Mars = Rotation of Mars/ time

Time = 24 hrs 37 minutes

Converting to seconds = 88620s

Tangential Speed of rotation = 21.4 × 10^6 m/ 88620s

= 241.48047845m/s

= 241.5 m/s

Step 2

revolution of Mars = 2 × π × d

d = 2.3 × 10^11m.

= 2 × π × 2.3 × 10^11m = 1.45 × 10^12m

Revolution of Mars = 687 days

Converting 687 days to seconds = 59356800s

Tangential Speed of Revolution of Mars = Revolution of Mars/ times

Tangential Speed of Revolution = 1.45 × 10^12m/595356800s

Tangential Speed of Revolution = 24420m/s

Comparing the Tangential Speed of Rotation with the Tangential speed of Revolution, we can see the GREATER ONE IS THE TANGENTIAL SPEED OF REVOLUTION.

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