Question

If a rock climber accidentally drops a 52.5-g piton from a height of 325 meters, what would its speed be just before striking the ground? ignore the effects of air resistance.

Answer 1

Ignoring air resistance, the Kinetic energy before hitting the ground will be equal to the potential energy of the Piton at the top of the rock.  
So we have 1/2 MV^2 = MGH 
V^2 = 2GH 
V = âš2GH 
V = âš( 2 * 9.8 * 325)  
V = âš 6370
 V = 79.81 m/s