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OLEGan [10]
3 years ago
11

If a rock climber accidentally drops a 52.5-g piton from a height of 325 meters, what would its speed be just before striking th

e ground? ignore the effects of air resistance.
Physics
1 answer:
alex41 [277]3 years ago
6 0
Ignoring air resistance, the Kinetic energy before hitting the ground will be equal to the potential energy of the Piton at the top of the rock.  
So we have 1/2 MV^2 = MGH 
V^2 = 2GH 
V = âš2GH 
V = âš( 2 * 9.8 * 325)  
V = âš 6370
 V = 79.81 m/s
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Describe how engineers designed a parachute to create the forces needed to slow down the falling person.
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Answer:

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     I = ∫ r² dm

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A very useful theorem is the parallel axis theorem that states that the moment of inertia with respect to another axis parallel to the center of mass is

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The mass of the arms is

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The arms are very thin, we will approximate them as a particle

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Let's write the equation

     I_{total} = ½ M R² + 2 (m D²)

Let's calculate

    I_{total} = ½ 56 0.20² + 2 4 0.20²

    I_{total} = 1.12 + 0.32

    I_{total} = 1.44 kg m²

b) if you separate the arms from the body, the distance D increases quadratically, so the moment of inertia must increase

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