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OLEGan [10]
3 years ago
11

If a rock climber accidentally drops a 52.5-g piton from a height of 325 meters, what would its speed be just before striking th

e ground? ignore the effects of air resistance.
Physics
1 answer:
alex41 [277]3 years ago
6 0
Ignoring air resistance, the Kinetic energy before hitting the ground will be equal to the potential energy of the Piton at the top of the rock.  
So we have 1/2 MV^2 = MGH 
V^2 = 2GH 
V = âš2GH 
V = âš( 2 * 9.8 * 325)  
V = âš 6370
 V = 79.81 m/s
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#1

A point on the outside of a spinning top whose rotational speed is constant.

Since the point at the top is at rest so it will not accelerate at all

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Since buoyant force is more than the weight so it will not at rest and move upwards with some acceleration


#2

A frictionless spinning merry go round.

Since spinning wheel accelerating due to centripetal force so it is non inertial frame

A falling rock.

Falling rock is accelerating due to gravity so it is again non inertial frame

A hot air balloon moving at 30 degrees east of north with no net force.

since hot air balloon is having no force on it so its acceleration is zero and its an inertial frame

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#3

Here net force on it is due to two given forces

F_1 = 4320 N towards right

F_2 = 4380 N towards left

so here net force is given as

F = F_2 - F_1

F = 4380 - 4320 = 60 N

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2 years ago
When an oxygen atom forms an ion, it gains two electrons
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Option B.
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I need help with 23 please.
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8 0
3 years ago
A mechanic pushes a 2.30 ✕ 103-kg car from rest to a speed of v, doing 4,800 J of work in the process. During this time, the car
Illusion [34]

The horizontal force applied is  160 N while the velocity is  2.03 m/s.

<h3>What is the speed of the car?</h3>

The work done by the car is obtained as the product of the force and the distance;

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F = ?

x = 30.0 m

W = 4,800 J

F = 4,800 J/30.0 m

F = 160 N

But F = ma

a = F/m

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a= 0.069 m/s

Now;

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u = 0/ms because the car started from rest

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v = 2.03 m/s

Learn more about force and work:brainly.com/question/758238

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