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3 years ago

The length of a garden is 25 m. Find the width knowing that the area is between 300 m2 I need it now pls

Mathematics

1 answer:

mars1129 [50]3 years ago

6 0

Answer: 12m

Step-by-step explanation:

Assuming the garden is a rectangular one, the area can be calculated by the formula:

Area = Length * Width

Given the length, one can find the width by making it the subject of the formula:

300 = 25 * Width

Width = 300 / 25

= 12 m

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Jackson runs a farm stand that sells bananas and grapes. Each pound of bananas sells for $1 and each pound of grapes sells for $

mars1129 [50]

Jackson sold 27 pounds of bananas and 12 pounds of grapes.

Given that Jackson runs a farm stand that sells bananas and grapes, and each pound of bananas sells for $ 1 and each pound of grapes sells for $ 2.25, and Jackson sold 15 more pounds of bananas than pounds of grapes and made $ 54 altogether, to determine the number of pounds of bananas sold and the number of pounds of grapes sold the following calculation must be performed:

25 x 1 + 10 x 2.25 = 25 + 22.50 = 47.50
26 x 1 + 11 x 2.25 = 26 + 24.75 = 50.75
27 x 1 + 12 x 2.25 = 27 + 27 = 54

Therefore, Jackson sold 27 pounds of bananas and 12 pounds of grapes.

Learn more about quantities in brainly.com/question/25823155

3 0

3 years ago

What are the domain and range of the function f(x)=(√x-7)+9?

Yanka [14]

Answer:

the domain of the function f(x) is $x\ge 7$

the range of the function f(x) is $f(x)\ge 9$

Step-by-step explanation:

Consider the parent function $y=\sqrt{x}.$

The domain og this function is $x\ge 0,$ the range of this function is $y\ge 0.$

The function $f(x)=\sqrt{x-7}+9$ is translated function $y=\sqrt{x}$ 7 units to the right and 9 units up, so

the domain of the function f(x) is $x\ge 7$

the range of the function f(x) is $f(x)\ge 9$

3 0

4 years ago

Ten increased by 6 times a number is the same as 4 less than 4 times the number

Gelneren [198K]

Express into algebraic form
10 + 6x = 4x - 4

5 0

4 years ago

I need help with these two questions

BlackZzzverrR [31]

Problem 4

Answer: 47

------------------------

Work Shown:

f(x) = x^2 - 7x + 3
f(x) = (x)^2 - 7(x) + 3
f(-4) = (-4)^2 - 7(-4) + 3 ... replace each x with -4
f(-4) = 16 - 7(-4) + 3
f(-4) = 16 + 28 + 3
f(-4) = 44 + 3
f(-4) = 47

============================================================

Problem 5

Answer: See the attached image for the table

------------------------

Work Shown:

Plug in n = 27 and we get...
C = 26 + 10*n
C = 26 + 10*27
C = 26 + 270
C = 296
The input n = 27 leads to the output C = 296. This means that 27 people will have the cost be $296

Do the same for n = 39
C = 26 + 10*n
C = 26 + 10*39
C = 26 + 390
C = 416
The input n = 39 leads to the output C = 416. This means that 39 people will have the cost be $416

and also n = 43 as well
C = 26 + 10*n
C = 26 + 10*43
C = 26 + 430
C = 456
The input n = 43 leads to the output C = 456. This means that 43 people will have the cost be $456

4 0

3 years ago

Which of the following expressions is equivalent to a3 + b3?

lubasha [3.4K]

ANSWER
${a}^{3} + {b}^{3} = (a + b)( {a}^{2 } - ab + {b}^{2} )$

EXPLANATION

To find the expression that is equivalent to
${a}^{3} + {b}^{3}$
we must first expand
${(a + b)}^{3}$
Then we rearrange to find the required expression.

So let's get started.

${(a + b)}^{3} = (a + b) {(a + b)}^{2}$

We expand the parenthesis on the right hand side to get,

${(a + b)}^{3} = (a + b) ( {a}^{2} + 2ab + {b}^{2} )$

We expand again to obtain,

${(a + b)}^{3} = {a}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {b}^{3}$

Let us group the cubed terms on the right hand side to get,

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2}b + 3a {b}^{2}$

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab (a+ b)$

We make the cubed terms the subject,

${(a + b)}^{3} - 3ab (a+ b) = {a}^{3} + {b}^{3}$

We factor to get,

$(a + b)({(a + b)}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We expand the bracket on the left hand side to get,

$(a + b)( {a}^{2} + 2ab + {b}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We finally simplify to get,

$(a + b)( {a}^{2} - ab + {b}^{2} ) = {a}^{3} + {b}^{3}$

5 0

3 years ago

Read 2 more answers