All categories

2 years ago

Moles of cations are in 1.35 mol of K2SO4

Chemistry

1 answer:

KatRina [158]2 years ago

6 0

1.35 mole of K₂SO₄ contain 2.7 moles of cation.

Cations are positive ions. They are the ions of metallic elements.

To obtain the answer to the question, we'll begin by calculating the number of mole of cations in 1 mole of K₂SO₄.

K₂SO₄ (aq) —> 2K⁺ (aq) + SO₄²¯ (aq)

<h3>Cation => K⁺</h3>

From the balanced equation above,

1 mole of K₂SO₄ contains 2 moles of K⁺ (i.e cation).

Finally, we shall determine the number of mole of cation in 1.35 mole of K₂SO₄. This can be obtained as follow:

1 mole of K₂SO₄ contains 2 moles of K⁺ (i.e cation).

Therefore, 1.35 mole of K₂SO₄ will contain = 1.35 × 2 = 2.7 moles of K⁺ (i.e cation).

Hence, we can conclude that 1.35 mole of K₂SO₄ contain 2.7 moles of cation

Learn more: brainly.com/question/24707125

You might be interested in

As carbon dioxide enters systemic blood, it causes more oxygen to dissociate from hemoglobin, which in turn allows more CO2 to c

vagabundo [1.1K]

Answer:

The correct answer is "False".

Explanation:

It is false that as carbon dioxide enters systemic blood, it causes more oxygen to dissociate from hemoglobin. Once an atom of oxygen binds to hemoglobin, hemoglobin change its shape and makes easier than a second and a third atom of oxygen binds towards it. This change in conformation makes no possible that carbon dioxide can cause that oxygen dissociates from hemoglobin.

5 0

3 years ago

216 J of energy is required to raise the temperature of a piece of aluminum from 15.0º C to to 35º C.

ddd [48]

Answer: 12g

Explanation:

The amount of energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = 216 joules

Mass of aluminium = ? (let unknown value be Z)

C = 0.90 JºC-1g-1

Φ = (Final temperature - Initial temperature)

= 35°C - 15°C = 20°C

Then, Q = MCΦ

216 J = Z x 0.90 JºC-1g-1 x 20°C

216 J = Z x 18 J°g-1

Z = (216J/18 J°g-1)

Z = 12g

Thus, the mass of the aluminium is 12grams

8 0

3 years ago

What is the pH of a solution with a H+ ion of 2×10-¹²?

kap26 [50]

Answer:

11.7

Explanation:

The pH is the negative logarithm of the concentration of H+ ions. If the concentration is 2×10-¹² the the pH will be -log(2×10-¹²) which is 11.698 which can be round up to 11.7.

5 0

3 years ago

The combustion of palmitic acid is represented by the chemical equation: C16H32O2(s) + 23O2(g) → 16 CO2(g) + 16 H2O(l) The magni

solniwko [45]

Answer:

The correct option is C

Explanation:

From the question we are told that

The reaction is

$C_{16}H_{32}O_2(g) + 23O_2(g) \to 16 CO_2(g) + 16 H_2O(l)$

Generally $\Delta H = \Delta U + \Delta N* RT$

Here $\Delta H$ is the change in enthalpy

$\Delta U$ is the change in the internal energy

$\Delta N$ is the difference between that number of moles of product and the number of moles of reactant

Looking at the reaction we can discover that the elements that was consumed and the element that was formed is $O_2$ and $CO_2$ and this are both gases so the change would occur in the number of moles

$\Delta H = \Delta U + [16 -23]* RT$

$\Delta H = \Delta U -7RT$

The negative sign in the equation tell us that the enthalpy $\Delta_r H$ would be less than the Internal energy $\Delta_r U$

4 0

3 years ago

(i) 1s 2 2s 2 2p 6 3s 1 (ii) 1s 2 2s 2 2p 6 3s 2 (iii) 1s 2 2s 2 2p 6 3s 2 3p 1 (iv) 1s 2 2s 2 2p 6 3s 2 3p 4 (v) 1s 2 2s 2 2p 6

Marizza181 [45]

Answer:

(V) 1s 2 2s 2 2p 6 3s 2 3p 5

Explanation:

Electron Affinity can be defined as the energy associated with a neutral atom, when an electron is added to form a negative ion.

1s 2 2s 2 2p 6 3s 2 3p 5 , is the electronic configuration of Chlorine.

The electron affinity is positive because it is an exorthermic reaction, meaning that, energy was released during the addition of an electron to the atom.

Cl (g) + e- -------> Cl- (g) = -349KJ/mol

5 0

3 years ago