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victus00 [196]
3 years ago
10

TIMED PLEASE HURRY WILL MARK BRAINLIEST

Mathematics
2 answers:
Nat2105 [25]3 years ago
6 0

Answer:

The answer is A) –273.15°C, good luck!

Ahat [919]3 years ago
5 0

Answer:

its a

Step-by-step explanation:

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A 75% decrease followed by a 50% increase is it greater than original less than original same as original
tresset_1 [31]
The correct answer is less than the original
Hope this helped ;)
3 0
4 years ago
Assume ABC DEF. If mA = 70 , mB = 47 , and mC = 63 , what is the measure of F? A. 63 B. 70 C. 47 D. Cannot be determined
kipiarov [429]
I'm assuming that the full statement is ΔABC is congruent to ΔDEF.

Given:
m∠A = 70
m∠B = 47
m∠C = 63

Since both triangles are congruent, the corresponding angles in ΔDEF also has the same measure as those in ΔABC.

m∠D = 70
m∠E = 47
m∠F = 63

The measure of angle F is 63.

5 0
3 years ago
Read 2 more answers
A boat has a ladder that's ten feet long, and hangs off the side of the boat,
anzhelika [568]

Answer:

2ft

Step-by-step explanation:

The tide doesn't effect the part of ladder that is underwater that is always 2ft

7 0
3 years ago
Kayleigh has $4500 in a savings account at the bank that earns 0.8% interest per year. How much
Sloan [31]

Answer:

Kayleigh will have a total of $4608.

Step-by-step explanation:

First, you use the formula, I=PRT (Interest=Principal, Rate, Time), then you distribute the numbers: (I=4500x0.8%x3) when you multiply them all, you get $108, then you lastly add 108 to 4500, and you get your final answer of $4608.

7 0
3 years ago
Read 2 more answers
The radius of a circle is decreasing at a rate of 6.56.56, point, 5 meters per minute. At a certain instant, the radius is 12121
Ilia_Sergeevich [38]

Answer:

The rate of change of the area of the circle is  approximately -490.09 \ m^2/min.

Step-by-step explanation:

Given:

\frac{dr}{dt} = -6.5 \ m/min

radius r =12 \ m

We need to find the rate of change of the area of the circle at that instant.

Solution:

Now we know that;

Area of the circle is given by π times square of the radius.

framing in equation form we get;

A= \pi r^2

to find the rate of change of the area of the circle at that instant we need to take the derivative on both side.

\frac{dA}{dt}=\frac{d(\pi r^2)}{dt}\\\\\frac{dA}{dt}= 2\pi r \frac{dr}{dt}

Substituting the given values we get;

\frac{dA}{dt}= 2\times \pi \times 12 \times -6.5\\\\\frac{dA}{dt}\approx -490.09 \ m^2/min

Hence The rate of change of the area of the circle is  approximately -490.09 \ m^2/min.

6 0
3 years ago
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