Answer: (a) 0.000083M/s, 0.000069M/s, 0.000052M/s, 0.000034M/s
(b) average reaction rate between t=0.0min to t=430.0min =0.000049M/s
(c) The average rate between t=54.0 and t=215.0min is greater than the average rate between t=107.0 and t=430.0min
Explanation:
Average reaction rate = change in concentration / time taken
(a) <em>after 54mins, t = 54*60s = 3240s</em>
average reaction rate = (1.58 - 1.85)M / (3240 * 0.0)s
= -0.27M/3240
= 0.000083M/s
<em>after 107mins, t = 107*60s = 6420s</em>
average reaction rate = (1.36 - 1.58)M/ (6420 - 3240)s
= -0.22M/3180s
= 0.000069M/s
<em>after 215mins, t = 215*60s = 12900s</em>
average reaction rate = (1.02 - 1.36)M/ (12900 - 6420)s
= -0.34M/6480s
= 0.000052M/s
<em>after 430mins,t = 430*60 = 25800s</em>
average reaction rate = (0.580 - 1.02)M / (25800 - 12900)s
= -0.44M/12900s
= 0.000034M/s
(b) <em>average reaction rate between t=0.0min to t=430.0min</em>
= (0.580 - 1.85)M/ (25800 - 0.0)s
= -1.27M/25800s
=0.000049M/s
(c) average reaction rate between t = 54.0min and t = 215.0min
= (1.02 - 1.58)M / (12900 - 3240)s
= -0.56M/9660s
= 0.000058M/s
average reaction rate between t=107.0 and t=430.0min
= (0.580 - 1.36)M / (25800 - 6420)s
= 0.78M /19380s
= 0.000040M/s
Therefore the average rate between t=54.0 and t=215.0min is greater than the average rate between t=107.0 and t=430.0min
