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Anna35 [415]
2 years ago
12

A way of describing a chemical change that indicates what substances were present before the change and what substances are pres

ent after the change is called a _____.
A. chemical equation
B. chemical formula
C. chemical bond
D. All of the above
E. None of the above
Chemistry
1 answer:
musickatia [10]2 years ago
7 0

Answer:

\\ \rm\dashrightarrow Chemical\: Equation

Explanation:

When a chemical change happens or chemical reaction happens something yields at reactants and something at products

Representing them is called chemical equation

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Julie takes a cold glass of clear, colorless liquid out of the refrigerator and puts it on the table. As the liquid warms up to
marysya [2.9K]
The bubbles indicate that there is a gas dissolved in the liquid, which may remain dissolved when the liquid is very cold, inside the refrigerator.


When the temperature of the liquid increases, it reduces its ability to dissolve the gas and the gas escapes (bubbles) from the liquid.


At the end, the behavior of the liquid permits  you to conclude that the  liquid is a mixture because it has a gas dissolved in it.
8 0
3 years ago
Read 2 more answers
The maximum depth of Lake Tahoe is 99.6 rod. How deep is Lake Tahoe in fathoms if one fathom-0.364 rod? ball part 250-300 fathom
Romashka [77]

Answer:

273.9 fathom

Explanation:

Fathom (ftm) and rod are the units of length used in the imperial and the U.S. customary systems.

Fathom is an unit used for the measurement of depth of water. It is equal to 1.8288 m.

Rod, also known as perch or pole, is equal to 5.0292 m.

∵ 1 fathom = 0.364 rod

and 1 rod = 2.75 fathom

∴ 99.6 rod = 99.6 × 2.75 fathom = 273.9 fathom

<u>Therefore, maximum depth of Lake Tahoe = 99.6 rod = 273.9 fathom</u>

6 0
3 years ago
Number 7 and 8 <br><br><br><br><br><br>Skjsjsjsjskksksksksksksjjsj<br>​
noname [10]

Answer:

B

B

Explanation:

the both have the same thing or something

3 0
2 years ago
Read 2 more answers
He balanced equation for the reaction of acetylene, c2h2, and oxygen in an acetylene torch is 2 c2h2 + 5 o2 → 4 co2 + 2 h2o. in
pickupchik [31]
Answer: 0.4 g

Explanation:

1) Balanced chemical equation:

2) 2C2H2 + 5 O2 → 4CO2 + 2 H2O

3) mole ratios:

2 mol C2h2 : 5 mol O2

4) Convert 0.13 g C2H2 into number of moles

n = mass in grams / molar mass

molar mass C2H2 = 2 *12g/mol + 2*1 g/mol = 26 g/mol

n = 0.13 g / 26 g/mol = 0.005 mol

5) Set the proportion with the unknown

5 mol O2             x
----------------- = ---------------
2 mol C2H2      0.005 mol C2H2

x = 0.005 mol C2H2 * 5 mol O2 / 2 mol C2H2 = 0.0125 mol O2

6) Convert 0.0125 mol O2 to grams

mass = number of moles * molar mass

molar mass of O2 = 32 g/mol

mass = 0.0125 mol * 32 g/mol = 0.4 g

Answer: 0.4 g
8 0
3 years ago
The rate of disappearance of HCl was measured for the following reaction:
AURORKA [14]

Answer: (a)  0.000083M/s,  0.000069M/s, 0.000052M/s,  0.000034M/s

(b) average reaction rate between t=0.0min to t=430.0min =0.000049M/s

(c) The average rate between t=54.0 and t=215.0min is greater than the average rate between t=107.0 and t=430.0min

Explanation:

Average reaction rate = change in concentration / time taken

(a) <em>after 54mins, t = 54*60s = 3240s</em>

average reaction rate = (1.58 - 1.85)M / (3240 * 0.0)s

= -0.27M/3240

= 0.000083M/s

<em>after 107mins, t = 107*60s = 6420s</em>

average reaction rate = (1.36 - 1.58)M/ (6420 - 3240)s

= -0.22M/3180s

= 0.000069M/s

<em>after 215mins, t = 215*60s = 12900s</em>

average reaction rate = (1.02 - 1.36)M/ (12900 - 6420)s

= -0.34M/6480s

= 0.000052M/s

<em>after 430mins,t = 430*60 = 25800s</em>

average reaction rate = (0.580 - 1.02)M / (25800 - 12900)s

= -0.44M/12900s

= 0.000034M/s

(b) <em>average reaction rate between t=0.0min to t=430.0min</em>

= (0.580 - 1.85)M/ (25800 - 0.0)s

= -1.27M/25800s

=0.000049M/s

(c) average reaction rate between t = 54.0min and t = 215.0min

= (1.02 - 1.58)M / (12900 - 3240)s

= -0.56M/9660s

= 0.000058M/s

average reaction rate between t=107.0 and t=430.0min

= (0.580 - 1.36)M / (25800 - 6420)s

= 0.78M /19380s

= 0.000040M/s

Therefore the average rate between t=54.0 and t=215.0min is greater than the average rate between t=107.0 and t=430.0min

6 0
3 years ago
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