Electrical energy is the starting and final energy of a battery
<span>they have to be selective permeable to filter out the waste products but allow the nutrients and blood cells to pass through. </span>
<h2>
Answer: A</h2>
Explanation because the distance covered is equal time intervals is the same or equal.
Answer:
The height of the object is 5007.4 miles.
Explanation:
Given that,
Weight of object = 200 lb
We need to calculate the value of 
Using formula of gravitational force

Put the value into the formula



We need to calculate the height of the object
Using formula of gravitational force

Put the value into the formula





Hence. The height of the object is 5007.4 miles.
Answer:
(a) The value of the ratio m₁/m₂ is 0.581
(b) the acceleration of the combined masses is 1.139 m/s²
Explanation:
Given;
The acceleration of force applied to M₁, a₁ = 3.10 m/s²
The same force applied to M₂ has acceleration, a₂ = 1.80 m/s²
Let this force = F
According Newton's second law of motion;
F = ma
(a) the value of the ratio m₁/m₂
since the applied force is same in both cases, M₁a₁ = M₂a₂

(b) the acceleration of m₁ and m₂ combined as one object under the action force F
F = ma


Therefore, the acceleration of the combined masses is 1.139 m/s²