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professor190 [17]
3 years ago
11

An engine jack is used to lift a 265-lb engine 6'. How much work, in ft-lb, is performed?

Engineering
1 answer:
Vlad [161]3 years ago
5 0

(-1)*exp(+i pi) = 1

formatted cleanly

2x2x2x2x2

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viktelen [127]
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3 0
3 years ago
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A heat pump cycle whose coefficient of performance is 2.5 delivers energy by heat transfer to a dwelling at a rate of 20kW.
12345 [234]

Answer:

a) 8kW

b) $128

Explanation:

Given the coefficient of performance of the heat pump cycle to be 2.5

Energy delivered by the heat pump = 20kW

a) net power required to operate the heat pump = Energy delivered / coefficient of performance

Net power required = 20/2.5

= 8kW

b) Given the cost of electricity is $0.08 for 1kWhour

Since net power required to operate heat pump = 8kW

If the heat pump operate for 200hours, total power required for a month = 8kW×200hours = 1600kWhour

since 1kWh of electricity costs $0.08, cost of electricity used in a month when the pump operates for 200hour will be 1600kWh×$0.08 which is equivalent to $128

8 0
3 years ago
Why is it important to know where your online information comes from?
statuscvo [17]

It is very important to know where online information comes from in order to validate, authenticate and be sure it's the right information

<h3>What are online information?</h3>

Online informations are information which are available on the internet such as search engines, social handles and other websites

In conclusion, it is very important to know where online information comes from in order to validate, authenticate and be sure it's the right information

Learn more about online information:

brainly.com/question/921157

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5 0
2 years ago
Velocity components in an incompressible flow are: v = 3xy + x^2 y: w = 0. Determine the velocity component in the x-direction.
cupoosta [38]

Answer:

Velocity component in x-direction u=-\frac{3}{2}x^2-\frac{1}{3}x^3.

Explanation:

   v=3xy+x^{2}y

We know that for incompressible flow

   \frac{\partial u}{\partial x}+\frac{\partial v}{\partial y}=0

\frac{\partial v}{\partial y}=3x+x^{2}

So   \frac{\partial u}{\partial x}+3x+x^{2}=0

\frac{\partial u}{\partial x}= -3x-x^{2}

By integrate with respect to x,we will find

u=-\frac{3}{2}x^2-\frac{1}{3}x^3+C

So the velocity component in x-direction u=-\frac{3}{2}x^2-\frac{1}{3}x^3.

3 0
3 years ago
1. A four-lane freeway (two lanes in each direction) is located on rolling terrain and has 12-ft lanes, no lateral obstructions
otez555 [7]

Answer:

Maximum number of vehicle = 308

Explanation:

See the attached file for the calculation.

6 0
3 years ago
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