Answer:
4. The velocity gradient at the wall is greater for a laminar boundary layer than a turbulent boundary layer.
Explanation:
This is false
Answer:
T(water)=50.32℃
T(air)=3052.6℃
Explanation:
Hello!
To solve this problem we must use the equation that defines the transfer of heat by convection, which consists of the transport of heat through fluids in this case water and air.
The equation is as follows!

Q = heat
h = heat transfer coefficient
Ts = surface temperature
T = fluid temperature
a = heat transfer area
The surface area of a cylinder is calculated as follows

Where
D=diameter=20mm=0.02m
L=leght=200mm)0.2m
solving

For water
Q=2Kw=2000W
h=5000W/m2K
a=0.01319m^2
Tα=20C

solving for ts


for air
Q=2Kw=2000W
h=50W/m2K
a=0.01319m^2
Tα=20C

Technician A is incorrect so that means Technician B is correct.
Answer:
a) The maximum possible heat removal rate = 2.20w
b) Fin length = 37.4 mm
c) Fin effectiveness = 89.6
d) Percentage increase = 435%
Explanation:
See the attached file for the explanation.
Answer:
Rate of Entropy =210.14 J/K-s
Explanation:
given data:
power delivered to input = 350 hp
power delivered to output = 250 hp
temperature of surface = 180°F
rate of entropy is given as

T = 180°F = 82°C = 355 K
Rate of heat = (350 - 250) hp = 100 hp = 74600 W
Rate of Entropy