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Zarrin [17]
3 years ago
15

What entrepreneurial activities do you know?are you capable of doing entrepreneurial activities

Engineering
1 answer:
kherson [118]3 years ago
5 0

Answer:

.,m

Explanation:

.,m

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A furnace uses preheated air to improve its fuel efficiency. Determine the adiabatic flame temperature when the furnance is oper
balu736 [363]

Answer:

2543 k

Explanation:

This problem can be resolved by applying the first law of thermodynamics

<u>Determine the adiabatic flame temperature</u> when the furnace is operating at a mass air-fuel ratio of 16 for air preheated to 600 K

attached below is a detailed solution

cp = 1200

8 0
3 years ago
QUESTIONS
tigry1 [53]

the answer is C cause drivers dont always follow the rules

8 0
4 years ago
Carbon dioxide gas enters a well-insulated diffuser at 20 lbf/in.2 , 500R, with a velocity of 800 ft/s through a flow area of 1.
inessss [21]

Answer:

Exit Temperature= T2=563.6 °R

Exit Pressure= P2= 30.06 lbf/in^2

Mass Flow rate=1.276 lb/sec

Explanation:

Answer is explained in detailed way in the attached files.

4 0
3 years ago
How much work is performed if a 400 lb weight is lifted 10 ft ?
Setler [38]

W = M*G*H

Work done = 400*10

w = 4000 ft.lb

hope it helps!

7 0
4 years ago
The fatigue data for a brass alloy are given as follows: Stress Amplitude (MPa) Cycles to Failure 170 3.7 × 104 148 1.0 × 105 13
prohojiy [21]

Answer:

i) S–N plot is attached

ii) fatigue strength = 100 MPa

iii) fatigue life = 5.62 x 10^(5) cycles

Explanation:

i) I have attached the S–N plot (stress amplitude versus logarithm of cycles to failure)

ii) The question says we should find the fatigue strength at 4 × 10^(6) cycles.

So let's find the log of this and trace it on the graph attached.

Log(4 × 10^(6)) = 6.6

From the graph attached, at log of cycle value of 6.6, the fatigue strength is approximately 100 MPa

iii) The question says we should find the fatigue life for 120 MPa.

Thus, from the graph, at stress amplitude of 120 MPa, the log of cycles is approximately 5.75.

Thus,the fatigue life will be the inverse log of 5.75.

Thus, fatigue life = 10^(5.75)

Fatigue life = 5.62 x 10^(5)

8 0
3 years ago
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