1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zarrin [17]
3 years ago
15

What entrepreneurial activities do you know?are you capable of doing entrepreneurial activities

Engineering
1 answer:
kherson [118]3 years ago
5 0

Answer:

.,m

Explanation:

.,m

You might be interested in
When you arrive at an intersection with a stop sign in your direction, if there is no marked stop
Illusion [34]

Answer:

C: Stop before entering the pedestrian crosswalk.

Explanation:

3 0
3 years ago
Read 2 more answers
A gas mixture containing 3 moles CO2, 5 moles H2 and 1 mole water is undergoing the following reactions CO2+3H2 →cH3OH + H2O Dev
Ilya [14]
Aaaaaaaaaaaaaaaaaaaaaa
7 0
3 years ago
The lattice constant of a simple cubic primitive cell is 5.28 Å. Determine the distancebetween the nearest parallel ( a ) (100),
skelet666 [1.2K]

Answer:

a)5.28 Å , b)3.73 Å , c)3.048 Å

Explanation:

the atoms are situated only at the corners of cube.Each and every atom in simple cubic primitive at the corner is shared with 8 adjacent unit cells.

Therefore, a particular unit cell consist only 1/8th part of an atom.

The lattice constant of a simple cubic primitive cell is 5.28 Å

We know formula of distance,

d = \frac{a}{\sqrt{h^{2}+k^{2}+l^{2}}}

a)(100)

a=5.28 Å

Distance = \frac{5.28 Å}{\sqrt{1^{2}+0^{2}+0^{2}}}=5.28 Å

b)(110)

Distance = \frac{5.28}{\sqrt{1^{2}+1^{2}+0^{2}}} = 3.73 Å

c)(111)

Distance= \frac{5.28}{\sqrt{1^{2}+1^{2}+1^{2}}}= 3.048 Å

6 0
3 years ago
An engineer measures a sample of 1200 shafts out of a certain shipment. He finds the shafts have an average diameter of 2.45 inc
Vadim26 [7]

Answer: 78.89%

Explanation:

Given : Sample size : n=  1200

Sample mean : \overline{x}=2.45

Standard deviation : \sigma=0.07

We assume that it follows Gaussian distribution (Normal distribution).

Let x be a random variable that represents the shaft diameter.

Using formula, z=\dfrac{x-\mu}{\sigma}, the z-value corresponds to 2.39 will be :-

z=\dfrac{2.39-2.45}{0.07}\approx-0.86

z-value corresponds to 2.60 will be :-

z=\dfrac{2.60-2.45}{0.07}\approx2.14

Using the standard normal table for z, we have

P-value = P(-0.86

=P(z

Hence, the percentage of the diameter of the total shipment of shafts will fall between 2.39 inch and 2.60 inch = 78.89%

7 0
3 years ago
Counter argument for why engineers dont make a positive change in the world.​
egoroff_w [7]

Answer:

They don't make a positive change in the world because they have made mistakes that aren't able to be made fixed and there are a lot of engineers who haven't study enough and know the important basis of coming to engineer.

3 0
3 years ago
Other questions:
  • WILL MARK BRAINLEST PLEASE HELP
    10·1 answer
  • Can anybody teach me how to make an app with flask and pygame together?​
    10·1 answer
  • what should be used to feed material into a machine? A.joy stick B.push stick C. your feet D. your hands​
    14·1 answer
  • Stainless steel ball bearings (rho = 8085 kg/m3 and cp = 0.480 kJ/kg·°C) having a diameter of 1.2 cm are to be quenched in water
    10·2 answers
  • PLEASE ANSWER FOR DRIVERS ED! WILL GIVE BRAINLIEST
    10·1 answer
  • What are the equipment requirements for windshields and side windows?
    13·1 answer
  • Which one of the following is not an economic want?
    6·1 answer
  • Technician A says that the low level brake fluid switch on a master cylinder will turn on the brake warning light when the syste
    9·1 answer
  • A composite shaft with length L = 46 in is made by fitting an aluminum sleeve (Ga = 5 x 10^3 ksi) over a
    14·1 answer
  • Calculate the acceleration of a 2000kg single engine airlane just before take off when the thrust of the engine is 500n?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!