Answer: LEAST-1/8 GREATEST-3/4
Step-by-step explanation:
Answer:
<em>24 minutes</em>
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Step-by-step explanation:
Given:
Distance per lap = 2 miles
Speed of Lou Lambert = 160 miles/hr
Speed of Ralph Redding = 170 miles/hr
Speed difference between the two = 170 - 160 = 10 miles/hr
Therefore, we can say that <em>Ralph gains 10 miles in 60 minutes </em>over Lou<em>.</em>
We have to find the time in which Ralph will gain 2 laps i.e. 2
2 = 4 miles.
Let us use unitary method to find the required time.
10 miles are gained by Ralph in 60 minutes
1 mile will be gained in 
4 miles will be gained in 6
4 = <em>24 minutes</em>
Y = 1 3 -x = left[y \right] = \left[ 3-x\right][y]=[3−x]
Answer:
Infinitely many solutions.
Step-by-step explanation:
Let's begin by carrying out the indicated multiplications, which must be done before any addition or subtraction:
2(8r+5)-3=4(4r-1)+11 becomes 16r + 10 - 3 = 16r - 4 + 11.
Subtracting 16r from both sides, we get 10 - 3 = - 4 + 11, or 7 = 7
This is always true, so we can conclude that this equation has infinitely many solutions.
(15 qt/hr) x (1/4 gal/qt) x (1/60 hr/min) =
(15) / (4 x 60) = 0.0625 gal/min