Answer:
Potential energy on surface of Mars is 6669000 J
Explanation:
As we know that the weight of the climber on the surface of Earth is given as 675 N
So weight of the climber on the Mars is given as
Now we know that gravitational Potential energy is given as
For this question we can use the combined gas law equation.
for a fixed amount of gas
where P - pressure , V - volume , T- temperature and k - constant
Where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
temperature in K
T1 = 12 °C + 273 = 285 K
T2 - 16 °C + 273 = 289 K
substituting the values in the equation
V = 1.00 mL
⁻Answer:
Ne=1.8 *10^37
Explanation:
Current density J=Iₐ /(πr²)
= 8/(π* (1.5*10⁻³/2)²)= 4.53*10⁶ A/m²
Drift velocity = J/ne =4.53*10⁶ /(8.5×1028 *1.6×10−19 ) = 3.33 ×10−4 m/s
volume = πr²h= π * (1.5*10⁻³/2)² * 3 = 5.3 ×10−6 m³
Ne=1.8 *10^37
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