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hichkok12 [17]
3 years ago
12

A golf ball was thrown with a speed of 25 m/sec at an angle of 65° above the horizontal. What is the horizontal distance travele

d by the ball before it hits the ground?
Physics
1 answer:
Ainat [17]3 years ago
6 0

Answer:

The horizontal distance traveled by the ball before it hits the ground is 48.85 meters.

Explanation:

It is given that,

Speed of golf ball, v = 25 m/s

Angle above horizontal or angle of projection, θ = 65°

We need to find the distance travelled by the ball before it hots the ground or in other words we need to find the range. It is given by R.

R=\dfrac{v^2\ sin2\theta}{g}

R=\dfrac{(25\ m/s)^2\ sin2(65)}{9.8\ m/s^2}

R = 48.85 m

So, the distance travelled by the ball before it hots the ground is 48.85 meters. Hence, this is the required solution.

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