Answer:
![\boxed {\boxed {\sf 4.5 \ m/s \ in \ the \ positive \ direction}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%204.5%20%5C%20m%2Fs%20%5C%20in%20%5C%20the%20%20%5C%20positive%20%5C%20direction%7D%7D)
Explanation:
We are asked to find the final velocity of the boat.
We are given the initial velocity, acceleration, and time. Therefore, we will use the following kinematic equation.
![v_f= v_i + at](https://tex.z-dn.net/?f=v_f%3D%20v_i%20%2B%20at)
The initial velocity is 2.7 meters per second. The acceleration is 0.15 meters per second squared. The time is 12 seconds.
= 2.7 m/s - a= 0.15 m/s²
- t= 12 s
Substitute the values into the formula.
![v_f = 2.7 \ m/s + (0.15 \ m/s^2)(12 \ s)](https://tex.z-dn.net/?f=v_f%20%3D%202.7%20%5C%20m%2Fs%20%2B%20%280.15%20%5C%20m%2Fs%5E2%29%2812%20%5C%20s%29)
Multiply the numbers in parentheses.
![v_f= 2.7 \ m/s + (0.15 \ m/s/s * 12 \ s)](https://tex.z-dn.net/?f=v_f%3D%202.7%20%5C%20m%2Fs%20%2B%20%280.15%20%5C%20m%2Fs%2Fs%20%2A%2012%20%5C%20s%29)
![v_f = 2.7 \ m/s + (0.15 \ m/s *12)](https://tex.z-dn.net/?f=v_f%20%3D%202.7%20%5C%20m%2Fs%20%2B%20%280.15%20%5C%20m%2Fs%20%2A12%29)
![\v_f=2.7 \ m/s + (1.8 \ m/s)](https://tex.z-dn.net/?f=%5Cv_f%3D2.7%20%5C%20m%2Fs%20%2B%20%281.8%20%5C%20m%2Fs%29)
![v_f=2.7 \ m/s + (1.8 \ m/s)](https://tex.z-dn.net/?f=v_f%3D2.7%20%5C%20m%2Fs%20%2B%20%281.8%20%5C%20m%2Fs%29)
Add.
![v_f=4.5 \ m/s](https://tex.z-dn.net/?f=v_f%3D4.5%20%5C%20m%2Fs)
The final velocity of the boat is <u>4.5 meters per second in the positive direction.</u>
Saturn is very commonly known for its rings
If I tell you that I traveled 30 miles in the last 2 hours, the only thing you can calculate is my average speed during those two hours. You can't tell anything about my acceleration or the direction in which I traveled.
Answer:
Yes the water amounts are the same.
Explanation: