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Kisachek [45]
2 years ago
15

What volume is occupied by 2.33 moles of an ideal gas at 0.953 atm

Chemistry
2 answers:
vfiekz [6]2 years ago
6 0
B is the correct answer I’m pretty
nekit [7.7K]2 years ago
4 0

Answer:

WhAT

Explanation:

WTH

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A solid is hard and the molecules are packed together, a liquid can move around freely because the molecules aren't as packed together :)
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How are tadpoles and larvae similar
Bad White [126]

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C. they both eat and grow a lot, i hope it helps

6 0
2 years ago
Imagine that you're doing an experiment that requires you to smell the odor of a chemical solution in a beaker. Which procedure
mixas84 [53]

The correct answer really is B.

If you are directed to break that rule then you better be in a high level chemistry class. When I taught things like that I insisted that students just wait until the chemical permeated the fume cabinet and even then I was always very nervous.

Sometimes you have to know when to ignore a bad direction. If you are working with chlorine, for example, you should be especially careful. That stuff was used in WWI as part of a chemical warfare technique. Many men suffered grotesque deaths by breathing it in, particularly if they were in trenches. Chlorine is heavier than air. It sinks to the lowest level.

7 0
3 years ago
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Suppose you have been given the task of distilling a mixture of hexane + toluene. Pure hexane has a refractive index of 1.375 an
miv72 [106K]

Explanation:

The given data is as follows.

         Refractive index of mixture = 1.456

        Refractive index of hexane = 1.375

        Refractive index of toulene = 1.497

Let mole fraction of hexane = x_{1}

and, mole fraction of toulene = x_{2}

Also,        x_{1} + x_{2} = 1

or,            x_{1} = 1 - x_{2}

Hence, calculate the mole fraction of hexane as follows.

        refractive index mixture= mole fraction hexane × ref index hexane + mole fraction toluene × ref index toluene.

              1.456 = (1 - x_{2}) \times 1.375 + x_{2} \times 1.497

               1.456 = 1.375 - 1.375x_{2} + 1.497x_{2}

               0.081 = 0.122x_{2}

                   x_{2} = \frac{0.081}{0.122}

                                = 0.66

Since,     x_{1} = 1 - x_{2}

                          = 1 - 0.66

                          = 0.34

Thus, we can conclude that mole fraction of hexane in your sample is 0.34.        

3 0
3 years ago
Using the reagents below, list in order (by letter, no period) those necessary to transform 1-chlorobutane into 1-butyne. Note:
aliya0001 [1]

Answer:

Explanation:1. NaNH2 (1-Butene)

CH3CH2CH2CH2Cl --------------> CH3CH2CH=CH2 + HCl (elimination reaction)

2. Br2, CCl4

CH3CH2CH=CH2 ---------------> CH3CH2CH(Br)CH2Br (Simple addition Reaction)

3. NaNH2 (1-Butyne)

CH3CH2CH(Br)CH2Br ----------------> CH3CH2C≡CH + 2HBr

Sodamide (NaNH2) is a very strong base and generally results in Terminal Alkynes when treated with Vicinal Dihalides.

Alcoholic KOH on the other hand results in the formation of Alkynes with triple bonds in the middle of the molecule.

3 0
2 years ago
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