Answer:
Certamente você conhece três dimensões: comprimento, largura e profundidade. Além disso, quando se pensa um pouco fora da caixa também seria possível adicionar a dimensão do tempo.
Provavelmente, algumas pessoas viajam na maionese quando toca-se nesse assunto. Vem em suas mentes universos paralelos e até mesmo realidades alternativas. Mas também não se trata disso.
Explanation:
Basicamente as dimensões são as facetas do que nós percebemos a ser realidade. Existem muitos debates sobre dimensões na física. Um dos que mais chamam a atenção se chama Teoria das Cordas.
r
Answer:
A fluid is a substance [ <em>liquid</em><em> </em><em>and</em><em> </em><em>gas</em><em> </em><em>state</em><em> </em>] in which motion of another substance in it is opposed due to viscous drag [ <em>viscosity</em><em> </em>]
Explanation:

Answer:
make contact in a way which fits the industry and is comfortable to you
Explanation:
Terri Duncan was a person that helped people going for interviews by offering them professional advice on how to compose and conduct themselves during an interview.
Terri Duncan also helps people going for interviews but providing them with the aid they need concerning what to say during an interview.
Terri Duncan recommends following up after an interview by making contact in a way which fits the industry and is also comfortable to you.
Answer:
Normal force = 0.326N
Explanation:
Given that:
mass released from rest at C = 3.7 g = 3.7 × 10⁻³ kg
height of the mass = 1.1 m
radius = 0.2 m
acceleration due to gravity = 9.8 m/s²
We are to determine the normal force pressing on the track at A.
To to that;
Let consider the conservation of energy relation; which says:
mgh = mgr + 1/2 mv²
gh = gr + 1/2 v²
gh - gr = 1/2v²
g(h-r) = 1/2v²
v² = 2g(h-r)
However; the normal force will result to a centripetal force; as such, using the relation
N =mv²/r
replacing the value for v² = 2g(h-r) in the above relation; we have:
Normal force = 2mg(h-r)/r
Normal force = 2 × 3.7 × 10⁻³ × 9.8 ( 1.1 - 0.2 )/ 0.2
Normal force = 0.065268/0.2
Normal force = 0.32634 N
Normal force = 0.326N