Answer : q = 6020 J, w = -6020 J, Δe = 0
Solution : Given,
Molar heat of fusion of ice = 6020 J/mole
Number of moles = 1 mole
Pressure = 1 atm
Molar heat of fusion : It is defined as the amount of energy required to melt 1 mole of a substance at its melting point. There is no temperature change.
The relation between heat and molar heat of fusion is,
(in terms of mass)
or,
(in terms of moles)
Now we have to calculate the value of q.

When temperature is constant then the system behaves isothermally and Δe is a temperature dependent variable.
So, the value of 
Now we have to calculate the value of w.
Formula used : 
where, q is heat required, w is work done and
is internal energy.
Now put all the given values in above formula, we get

w = -6020 J
Therefore, q = 6020 J, w = -6020 J, Δe = 0
Answer:
200 watts
Explanation:
First we have to find total work:
W =F(d)
W = 400J
Then plug that answer into the Power formula.
P = W/(t_f-t-i)
P = 400/2s
P = 200 W
Answer:
<u>390g</u>
Explanation:
it's moles actually...
Molar mas of CaF2 is =78g/mol
It means 78g per mole...Si If you have 5 moles..that means you have...
78*5g of CaF2...