<h2>
Hello!</h2>
The answer is:
The temperature will be the same, 37°C.
<h2>
Why?</h2>
Since from the statemet we know the first temperature, pressure and volumen of a gas, and we need to calculate the new temperature after the pressure and the volume changed, we need to use the Combined Gas Law.
The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using Boyle's Law, Gay-Lussac's Law and Charles's Law.
The law establishes the following equation:
Where,
is the first pressure.
is the first volume.
is the first temperature.
is the second pressure.
is the second volume.
is the second temperature.
Then, we are given the following information:
So, isolating the new temperature and substituting the given information, we have:
Hence, we have that the temperature will not change because both pressure and volume decreased and increased proportionally, creating the same relationship that we had before the experiment started.
The temperature will be the same, 37°C
Have a nice day!
Answer:
4.Electronic configuration
Explanation:
The number of digits in the electronic configuration tells you how many shells are in an atom.
crystallization is a process which helps to separate a pure solid from a solution in its crystal form. This is the in use to purify solid. For an example the salt we get from seawater can have many impurities in it. Hence, the process of crystallization is in use to remove these impurities.
Sugar and salt are examples of products where crystallization does not only serve as separation/purification technique, but where it is also responsible for getting crystals with the right size (and shape) for further application of the products.
<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>
Over the course of a reaction the energy changes forms, in the beginning it may be used to produce a set of products, but in the end it can produce energy in the form of a combustion reaction.
Answer:
-177.9 kJ.
Explanation:
Use Hess's law. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2Ca(s) + O2(g) → 2CaO(s) ΔH = -1269.8 kJ We need to get rid of the Ca and O2 in the equations, so we need to change the equations so that they're on both sides so they "cancel" out, similar to a system of equations. I changed the second equation. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ The sign changes in the second equation above since the reaction changed direction. Next, we need to multiply the first equation by two in order to get the coefficients of the Ca and O2 to match those in the second equation. We also multiply the enthalpy of the first equation by 2. 2Ca(s) + 2CO2(g) + O2(g) → 2CaCO3(s) ΔH = -1625.6 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ Now we add the two equations. The O2 and 2Ca "cancel" since they're on opposite sides of the arrow. Think of it more mathematically. We add the two enthalpies and get 2CaO(s) + 2CO2(g) → 2CaCO3(s) and ΔH = -355.8 kJ. Finally divide by two to get the given equation: CaO(s) + CO2(g) → CaCO3(s) and ΔH = -177.9 kJ.
