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Nastasia [14]
3 years ago
14

Ice melts to form water. And water freezes to form ice. Choose the TRUE statement about these changes.

Chemistry
2 answers:
Dmitrij [34]3 years ago
4 0

Answer:

A. Both freezing and melting are physical changes.

Explanation:

Even if you were to freeze water, the molecules are still water molecules, and vise versa with melting it.

vovikov84 [41]3 years ago
3 0

Answer: Option A) Both melting and freezing are physical changes.

Explanation:

A physical change is one which is easily reversible and in which no new substances are formed.

Hence, since ice melts to form water (melting), and water freezes to form ice back (freezing), both melting and freezing are easily reversible and do not form new products.

Thus, both melting and freezing are physical changes.

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bagirrra123 [75]
Answer is: <span>A. Fracking reduces U.S. dependency on oil and gas from other countries..
Other answers are not bad side of fracking.
</span>Fracking is technique in which rock is fractured by a pressurized liquid and is used in <span>to create cracks in the rock formations through which </span>natural gas<span>, </span>petroleum<span> will flow more freely.</span>
7 0
3 years ago
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HURRY WILL MARK BRAINILEST
natita [175]

Answer:

Explanation:

diffusion has already occurred

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Assume the molality of isoborneol in your product is 0.275 mol/kg. What is the melting point of your impure sample given that th
aliina [53]

Answer:

168°C is the melting point of your impure sample.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = T_f = ?

Depression in freezing point = \Delta T_f

Depression in freezing point  is also given by formula:

\Delta T_f=i\times K_f\times m

K_f = The freezing point depression constant

m = molality of the sample  = 0.275 mol/kg

i = van't Hoff factor

We have: K_f = 40°C kg/mol

i = 1 (  non electrolyte)

\Delta T_f=1\times 40^oC kg/mol\times 0.275 mol/kg

\Delta T_f=11^oC

\Delta T_f=T- T_f

T_f=T- \Delta T_f=179^oC-11^oC=168^oC

168°C is the melting point of your impure sample.

4 0
3 years ago
During a lab, you heat 1.62 g of a CoCl2 hydrate over a Bunsen burner. After heating, the final mass of the dehydrated compound
sashaice [31]
Answer is: formula of hydrate is CoCl₂· 6H₂O -c<span>obalt(II) chloride hexahydrate
</span>m(CoCl₂· xH₂O) = 1,62 g.
m(CoCl₂) = 0,88 g.
n(CoCl₂) = m(CoCl₂) ÷ M(CoCl₂)
n(CoCl₂) = 0,88 g ÷ 130 g/mol
n(CoCl₂) = 0,0068 mol.
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m(H₂O) = 0,74 g.
n(H₂O) = m(H₂O) ÷ m(H₂O) 
n(H₂O) = 0,74 g ÷ 18 g/mol
n(H₂O) = 0,041 mol.
n(CoCl₂) : n(H₂O) = 0,0068 mol : 0,041 mol.
n(CoCl₂) : n(H₂O) = 1 : 6.
8 0
3 years ago
What is the coefficient for oxygen in the balanced equation? C 5H 12 + ? O2 → ? CO2 + ? H2O. 2 4 5 6 8
Temka [501]

Answer:

8

Explanation:

When you balance the entire equation, you should get:

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6 0
3 years ago
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