A flash of red light and a flash of blue light enter a glass cube perpendicular to its surface at the same time. after passing through the block, the red light pulse exits first.
For any medium, other than vacuum, the index of refraction for red light is slightly lower (closer to 1 ) than that for blue light. This means that when light goes from vacuum (or air) into glass, the red light deviates from its original direction less than does the blue light. Also, as the light reemerges from the glass into vacuum (or air), the red light again deviates less than the blue light. If the two surfaces of the glass are parallel to each other, the red and blue rays will emerge traveling parallel to each other, but displaced laterally from one another.
what is refractive index?
The ratio between the speed of light in medium to speed in a vacuum is the refractive index. When light travels in a medium other than the vacuum, the atoms of that medium continually absorb and re-emit the particles of light, slowing down the speed light.
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Answer:
distance must be = 330 × 5/2
= 330×2.5
=825m
Answer:
C
Explanation:
momentum = mass ×velocity
A. mv = 200
B. mv = 300
C. mv= 400
D. mv= 200
highest is C.
Answer:
The angle from the normal is 15.1°.
Explanation:
We can find the angle by using Snell's law:
Where:
n₁: is the first medium (glass) = 1.5
n₂: is the second medium (air) = 1.0
θ₁: is the first angle (in the glass) = 10°
θ₂: is the second angle (in the air) =?
Therefore, the angle from the normal is 15.1°.
I hope it helps you!
Answer:
497.143 nm.
Explanation:
Diffraction grating experiment is actually done by passing light through diffraction glasses, the passage of the light causes some patterns which can be seen on the screen. This is because light is a wave and it can spread.
The solution to the question is through the use of the formula in the equation (1) below;
Sin θ = m × λ. ---------------------------------(1).
Where m takes values from 0, 1, 2, ...(that is the diffraction grating principal maxima).
Also, m × λ = dc/ B -------------------------------------------(2).
We are to find the second wavelength, therefore;
λ2 =( m1/c1) × (c2/m2) × λ1 ------------------------(3).
Where c1 and c2 are the order maximum and m = order numbers. Hence;
λ2 = (1/ .350) × (.870/3) × 600 = 497.143 nm.
