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dexar [7]
3 years ago
12

1. What is a half-life?

Chemistry
1 answer:
irina [24]3 years ago
3 0
<h2>Answer:</h2>

<h2>Half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay (change spontaneously into other nuclear species by emitting particles and energy), or, equivalently, the time interval required for the number of disintegrations per second of a radioactive ..!!</h2><h2 /><h2 />

<h2>Hopefully u will satisfy with my answer..!!</h2><h2>Please Mark on brainleast please..!!</h2>

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2 A 3-meter-long ramp was used to lift gold into railroads for transfers. The railroads were 1 meter off the ground. What was th
Nataliya [291]

Answer:

3

Explanation:

For an ideal ramp, M.A/V.R = 1 where M.A = mechanical advantage and V.R = velocity ratio.

Now, V.R = distance moved by effort, d'/distance moved by load, d = d'/d

Now, d' = 3 m and d = 1 m.

So, V.R = d'/d = 3 m/1 m = 3

From M.A/V.R = 1

M.A = V.R = 3

So, the ideal mechanical advantage of the ramp M.A = 3  

6 0
3 years ago
The atomic symbol Superscript 206 subscript 82 upper P b. represents lead-206 (Pb-206), an isotope that has 82 protons and 124 n
Serggg [28]

Answer:

\left \{ {{y=206} \atop {x=82}}Pb \right.

Explanation:

isotopes are various forms of same elements with different atomic number but different mass number.

Radioactivity is the emission of rays or particles from an atom to produce a new nuclei. There are various forms of radioactive emissions which are

  • Alpha particle emission  \left \{ {{y=4} \atop {x=2}}He \right.
  • Beta particle emission    \left \{ {{y=0} \atop {x=-1}}e \right.
  • gamma radiation             \left \{ {{y=0} \atop {x=0}}γ \right.

in the problem the product formed after radiation was Pb-206. isotopes of lead include Pb-204, Pb-206, Pb-207, Pb-208. they all have atomic number 82. which means the radiation cannot be ∝ or β since both radiations will alter the atomic number of the parent nucleus.

Only gamma radiation with \left \{ {{y=0} \atop {x=0}}γ \right. will produce a Pb-206 of atomic number 82 and mass number 206 , since gamma ray have 0 mass and has 0 atomic number.equation is shown below

\left \{ {{y=206} \atop {x=82}}Pb\right ⇒ \left \{ {{y=206} \atop {x=82}}Pb\right +  \left \{ {{y=0} \atop {x=0}}γ\right.

Thus the atomic symbol is \left \{ {{y=206} \atop {x=82}}Pb\right

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<span>It contains 6.02mc001-2 particles of a given substance</span>
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