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nikitadnepr [17]
4 years ago
9

A 55 meter rope is lying on the floor and has has a weight of 4040 N in total. How much work is required to lift up one end of t

he rope to a height of 33 meters
Physics
1 answer:
Kazeer [188]4 years ago
6 0

Answer:

Explanation:

Given

Length of rope L=55\ m

Weight of rope W=4040\ N

weight density \lambda =\frac{4040}{55}=73.45\ N/m

Work done to lift rope 33 m

W=\int_{0}^{33}\lambda hdh

W=\int_{0}^{33}73.45hdh

W=73.45\left [ \left ( \frac{h^2}{2}\right )\right ]^{33}_0

W=39.993\ kJ      

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a low tide and a high tide occur in the oceans two times each day. which factor has the greatest effect on the size of the tides
Dmitrij [34]

Answer:

The gravitational pull from the Moon has the greatest effect on the size of the tides.

Hope this helps, :)

7 0
3 years ago
Under electrostatic conditions, the electric field just outside the surface of any charged conductor:
lesantik [10]

Answer:

D. is always perpendicular to the surface of the conductor

Explanation:

1) Answer is (D) option. Electric field just outside surface of charged conductor is normal to conductor at that point.

It can be explained on the basis of the fact that, Electric field inside conductor under static condition is zero. As a result potential difference between any two points with in conductor is zero. So whole of conductor is equipotential body.

Equipotential surface and Electric field lines always cut at 90 degrees to each other. Conductor being equipotential body, Electric field lines starting or terminating at conductor must be normal to surface. Hence electric field just outside conductor is perpendicular or normal to surface.

6 0
3 years ago
Two parallel rods are each 0.69 m in length. They are attached at their centers to a spring that is initially neither stretched
diamong [38]

Answer:

Explanation:

Let the separation required be d .

Force between rod = 10⁻⁷ x  2 I₁ I₂ L / d

where I₁ and I₂ are current in them , d is distance of separation and L is length of wire .

Force between rod = 10⁻⁷ x  2 x 1200 x  1200 x .69  / d

= .1987 /d

Restoring Force by spring = k x where k is force constant and x is compression .

= 130 x .03

= 3.9 N

For balancing

Restoring Force by spring = Force between rod

.1987 /d = 3.9

d = .1987 /3.9

= .0509 m

= 5.09 cm .

5 0
3 years ago
Ranboo <br><br> ⏚⟒⟒⌿<br><br> :) &lt;3 have a good day
bearhunter [10]
Ranboo oobnar have a good day
4 0
3 years ago
Read 2 more answers
If the core of jupiter is 30,000 celcius and it is five times hotter than the sun, what's the temperature of the surface of the
VMariaS [17]
Let, the temperature of Sun's surface = c

So, 5c = 30, 000
c = 30,000 / 5
c = 6,000

In short, Your Answer would be 6000

Hope this helps!
6 0
4 years ago
Read 2 more answers
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