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OLEGan [10]
4 years ago
5

Charging an object without touching it is called?

Physics
1 answer:
Airida [17]4 years ago
5 0
<span>Charging by induction</span>
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The velocity of an object is the distance it travels per unit time. Suppose the velocity of a gilding bird is measured to be 52.
Elanso [62]

Answer:

d=7.115s

Explanation:

What problem says can be written mathematically as:

v=\frac{d}{t}

Where:

v=Velocity\\t=Time\\d=Distance

The problem itself it's really simple, we only need to replace the data provided in the previous equation, but first, let's convert the units of the velocity from cm/s to m/s because we have to work with the same units and working in meters is the most apropiate action, because is the base unit of length in the International System of Units:

52\frac{cm}{s} *\frac{1m}{100cm} =0.52\frac{m}{s}

Now, we can replace the data in the equation and find the time it will take the bird to travel 3.7 m:

0.52=\frac{3.7}{t}

Solving for t, multiplying by t both sides, and dividing by 0.52 both sides:

t=\frac{3.7}{0.52} =7.115384615s\approx7.115s

5 0
3 years ago
A skydiver free falls from rest. How long does it take for the skydiver to reach 7 m/s?
aev [14]

Answer:

<em>The skydiver needs 0.71 seconds to reach 7 m/s</em>

Explanation:

<u>Free Fall Motion </u>

When an object is dropped in free air (no friction) from a certain height h, it follows a free-fall motion, whose acceleration is due exclusively to gravity. The speed at a moment t when the object is dropped (from rest) is:

V_f=gt

We need to find How long does the skydiver needs to reach 7 m/s. We solve for t

\displaystyle t=\frac{V_f}{g}

\displaystyle t=\frac{7}{9.8}

t=0.71\ sec

The skydiver needs 0.71 seconds to reach 7 m/s

5 0
3 years ago
Mr. Tolman believes that our universe is expanding, but with all of the gravitational force from the celestial bodies of space,
sattari [20]
The correct answer is A I believe but I may not be correct. Either A or B
8 0
3 years ago
The latent heat of vaporization for water at room temperature is 2430 J/g.
alukav5142 [94]

Answer:

1)   kinectic energy=7.26*10^-^2^0J

2)  V= 2.0m/s

3)  T=3.5*10^3K

4)  The Molecules do not burn because of the presences of hydrogen bond in place

Explanation:

From the question we are told that

latent heat of vaporization for water at room temperature is 2430 J/g.

1)Generally in determining the molar mass of water evaporated we have that

-One mole (6.02 x 10. 23 molecules)

-Molar mass of water is 18.02 g/mol

Mathematically the mass of water is give as

   

  M=\frac{18.02}{6.02*10^-^2^6}

  M=3*10^-^2^3g

Therefore

  kinectic energy=2430J/g*3*10^-^2^3g

 kinectic energy=7.26*10^-^2^0J

b)Generally the evaporation speed V is given asV= \sqrt{\frac{K.E*2}{m} }

Mathematically derived from the equation

\frac{1}{2} mv^2 =K.E

To Give

V= \sqrt{\frac{K.E*2}{m} }

V= \sqrt{\frac{7.26*10^-^2^0J*2}{3*10^-^2^3g} }

V= 2.0m/s

c)Generally the equation for velocity   Vrms=\sqrt{\frac{3RT}{M} }

Therefore

Effective temperature T is given by

      T=\frac{\sqrt{v}*m}{R}

where

     T=\frac{\sqrt{2.0m/s}*6.02*10^-^2^6}{0.082057 L atm mol-1K-1}

     T=3.5*10^3K

4) The Molecules do not burn because of the presences of hydrogen bond in place

3 0
3 years ago
A marching band is practicing. The band director sees the drum major hit a drum. How far away is the director if he hears the dr
ivanzaharov [21]

Answer:

825 m

Explanation:

330 m/s

1 / 0.40 = 2.5

330 x 2.5 = 825

7 0
3 years ago
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