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3 years ago

What is the maximum number of orbitals in the p sublevel?

Physics

1 answer:

dedylja [7]3 years ago

7 0

Answer:

3 orbitals

Explanation:

The p sublevel can carry a maximum of 6 electrons. Therefore it must be made of 3 orbitals which each, as in any orbital of any other sublevel, can carry 2 electrons. So there is a p sub x orbital, p sub y orbital and p sub z orbital which are all orthogonal to each other.

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The pupil of a cat's eye narrows to a slit width of 0.5 mm in daylight. What is the angular resolution of the cat's eye in dayli

Elenna [48]

Answer:

C. 10⁻³ rads

Explanation:

Here, we shall use Rayleigh's Criterion to find out the angular resolution of Cat's eye during day light. Rayleigh's Criterion is written as follows:

θ = λ/a

where,

θ = angular resolution of Cat's eye = ?

λ = wavelength = 500 nm = 5 x 10⁻⁷ m

a = slit width of eye = 0.5 mm = 5 x 10⁻⁴ m

Therefore,

θ = (5 x 10⁻⁷ m/5 x 10⁻⁴ m)

Therefore,

θ = 0.001

θ = Sin⁻¹(0.001)

θ = 0.001 rad = 1 x 10⁻³ rad

Hence, the correct answer is:

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2 years ago

How should the student change the circuit to give negative values for current and

dmitriy555 [2]

Answer:

Flip the cell.

Explanation:

This reverses direction of energy transfer.

Alternatively, flip ammeters and voltmeters to give negative readings.

what do penguins eat for lunch?

Ice-burgers!

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2 years ago

Why is this a scientific question?

defon

The 3rd one. The question can be tested by a systematic procedure

7 0

3 years ago

Read 2 more answers

What is the collective noun of chocolate

Vedmedyk [2.9K]

Answer:

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3 years ago

Denial cycled at 6 mph for 0.8 h. Then he jogged at 2 mph for

dexar [7]

<h3>Deniel's average speed for the total</h3><h3>distance is 3.6 mph</h3>

Average speed is difined as the total distance travelled divided by the total time required to cover the distance. Mathematically, it is expressed as:

$Ave. Speed = \frac{Total distance }{Total time}$

To obtain the average speed of Daniel, we shall determine the distance travelled in each case. This is illustrated below:

Speed 1 (S₁) = 6 mph

Time 1 (t₁) = 0.8 h.

<h3>Distance 1 (D₁) =? </h3>

$Speed = \frac{Distance}{Time} \\\\S_{1} = \frac{D_{1}}{t_{1}} \\\\6 = \frac{D_{1}}{0.8}$

Cross multiply

D₁ = 6 × 0.8

Speed 2 (S₂) = 2 mph

Time 2 (t₂) = 1.2 h.

<h3>Distance 2 (D₂) =? </h3>

$S_{2} = \frac{D_{2}}{t_{2}}\\\\2 = \frac{D_{2}}{1.2}$

Cross multiply

D₂ = 2 × 1.2

Next, we shall determine the total time. This can be obtained as follow:

Time 1 (t₁) = 0.8 h.

Time 2 (t₂) = 1.2 h.

<h3>Total time (T) =? </h3>

T = t₁ + t₂

T = 0.8 + 1.2

Next, we shall determine the total distance. This can be obtained as follow:

Distance 1 (D₁) = 4.8 mile

Distance 2 (D₂) = 2.4 mile

<h3>Total distance (D) =?</h3>

D = D₁ + D₂

D = 4.8 + 2.4

Finally, we shall determine the average speed of Daniel. This can be obtained as follow:

Total time = 2 h

Total distance = 7.2 mile

<h3>Average speed =?</h3>

$Ave. speed = \frac{Total distance }{Total time} \\\\Ave. speed = \frac{7.2 }{2}$

<h3>Average speed = 3.6 mph</h3><h3 />

Therefore, the average speed of Daniel is 3.6 mph

Learn more: brainly.com/question/680492

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3 years ago