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never [62]
1 year ago
15

7. A 78-kg skydiver has a speed of 62 m/s at an altitude of 870 m above the ground.

Physics
1 answer:
miv72 [106K]1 year ago
8 0

The kinetic energy, potential energy and total mechanical energy possessed by the skydriver are 1.5 × 10⁵ Joule, 6.7 × 10⁵ Joule and 8.2 × 10⁵ Joule respectively.

To find the answer, we need to know about the expression of kinetic energy and potential energy.

<h3>What are the expressions of kinetic energy and potential energy?</h3>
  • Mathematically, kinetic energy= 1/2 × mass × velocity²
  • Gravitational potential energy near the earth surface= mass × g × height on the earth surface

<h3>What's the kinetic energy, potential energy and total mechanical energy of the 78kg skydriver at 870 m on earth surface with 62 m/s velocity?</h3>
  • Kinetic energy= 1/2 × 78 × 62² = 1.5 × 10⁵ Joule
  • Potential energy= 78×9.8×870= 6.7× 10⁵ Joule
<h3>What's the total mechanical energy?</h3>
  • Mechanical energy= kinetic energy+ potential energy
  • 1.5 × 10⁵ Joule + 6.7× 10⁵ Joule = 8.2× 10⁵ Joule

Thus, we can conclude that the kinetic energy, potential energy and total mechanical energy possessed by the skydriver are 1.5 × 10⁵ Joule, 6.7 × 10⁵ Joule and 8.2 × 10⁵ Joule respectively.

Learn more about the kinetic energy, potential energy and mechanical energy here:

brainly.com/question/17051553

#SPJ1

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In a simple machine, the energy input is 120 J. If the efficiency of the machine is 80%, calculate the energy output
pashok25 [27]

Answer:

<h2>96 Joules</h2>

Explanation:

We know that efficiency is the ratio of output power by input power. i.e. Efficiency describes the quality of machine or system how good it is.

Solution,

Energy input of system = 120 J

Efficiency = 80% = \frac{80}{100}  = 0.8

Now,

According to definition,

Efficiency = \frac{output}{input}

Cross multiplication:

output \:  =  \: 0.8 \times 120

Calculate the product

output \:  = 96 \: joules

Hope this helps...

Good luck on your assignment...

4 0
3 years ago
A charge per unit length given by l(x) = bx, where b = 12 nc/m2, is distributed along the x axis from x = +9.0 cm to x = +16 cm.
Pavel [41]
Hopefully this will help you.

4 0
2 years ago
Nuclear power plants produce useful energy by controlling the process of?
Mandarinka [93]
Nuclear fusion is thed answer

5 0
3 years ago
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If the focal length of a concave mirror is 18cm, find its radius of curvature.
Galina-37 [17]

Given :

The focal length of a concave mirror is 18 cm.

To Find :

The radius of curvature of the concave mirror.

Solution :

We know,

\text{Focal length}=\dfrac{\text{Radius of curvature}}{2}\\\\F=\dfrac{R}{2}\\\\R = 18\times 2\ cm\\\\R = 36 \ cm

Therefore, the radius of curvature of concave mirror is 36 cm.

Hence, this is the required solution.

8 0
3 years ago
A light-rail commuter train accelerates at a rate of 1.35 m/s. D A 33% Part (a) How long does it take to reach its top speed of
Dennis_Churaev [7]

Answer:

a) 17.49 seconds

b) 13.12 seconds

c) 2.99 m/s²

Explanation:

a) Acceleration = a = 1.35 m/s²

Final velocity = v = 85 km/h = 85\frac{1000}{3600}=23.61\ m/s

Initial velocity = u = 0

Equation of motion

v=u+at\\\Rightarrow 23.61=0+1.35t\\\Rightarrow t=\frac{23.61}{1.35}=17.49\ s

Time taken to accelerate to top speed is 17.49 seconds.

b) Acceleration = a = -1.8 m/s²

Initial velocity = u = 23.61\ m/s

Final velocity = v = 0

v=u+at\\\Rightarrow 0=23.61-1.8t\\\Rightarrow t=\frac{23.61}{1.8}=13.12\ s

Time taken to stop the train from top speed is 13.12 seconds

c) Initial velocity = u = 23.61 m/s

Time taken = t = 7.9 s

Final velocity = v = 0

v=u+at\\\Rightarrow 0=23.61+a7.9\\\Rightarrow a=\frac{-23.61}{7.9}=-2.99\ m/s^2

Emergency acceleration is 2.99 m/s² (magnitude)

6 0
3 years ago
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