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marusya05 [52]
3 years ago
7

Question 10 (1 point)

Chemistry
1 answer:
levacccp [35]3 years ago
4 0
The empirical formula gives the relative ratio of atoms in each element. Therefore, it simplifies the whole numbers. For example C2H6 can be reduced to CH3 because they share the greatest common factor (2). The answer to this question would be #1. C4H10 can be reduced to C2H5 because 4 and 10 are both divisible by 2. C2H5 can not be reduced any further. All of the other options do not have a greatest common factor making them a empirical formula.
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Answer:

C

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A - Crude oil is composed for hundreds of hydrocarbon, not less than ten.

B - Is formed in specific conditions of temperature and pressure

C - It's fractionated to form gasoline, lubricants, CH4, plastics and many other products made of hydrocarbon.

D - We have crude oil located more than 4000 yards below the surface in countries like Brazil

E - The crude oil is very thick and don't have an specific usage, so we need to refine it.

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Part A The first step to engineering is to define the problem. Write down the problem the students have to solve, and describe t
Elena L [17]

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Explanation:

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2 years ago
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butalik [34]

Answer:

C and D

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The pH of lemon juice is 2, and the pH of orange juice is 4. Which of these is more acidic, and by how much? What does this mean
katovenus [111]

Explanation:

The pH is a 1 to 14 scale that measures how acidic or basic is a solution, at lowest number the solution will be acid, in 7 the solution will be neutral, and in higher values will be basic. It is a  logarithmic scale, so with each number you move, the acidity or basicity will be increased by a factor of 10. So, lemon juice is more acidic than orange juice by a factor of 100.

5 0
3 years ago
When 0.620 gMngMn is combined with enough hydrochloric acid to make 100.0 mLmL of solution in a coffee-cup calorimeter, all of t
OleMash [197]

Answer:

The enthalpy change during the reaction is -199. kJ/mol.

Explanation:

Mn(s)+2HCl(aq)\rightarrow  MnCl_2(aq)+H_2(g)

Mass of solution = m

Volume of solution = 100.0 mL

Density of solution = d = 1.00 g/mL

m=1.00 g/mL\times 100.0 mL = 100 g

First we have to calculate the heat gained by the solution in coffee-cup calorimeter.

q=m\times c\times (T_{final}-T_{initial})

where,

m = mass of solution = 100 g

q = heat gained = ?

c = specific heat = 4.18 J/^oC

T_{final} = final temperature = 23.1^oC

T_{initial} = initial temperature = 28.9^oC

Now put all the given values in the above formula, we get:

q=100 g \times 4.18 J/^oC\times (28.9-23.1)^oC

q=2,242.4 J=2.242 kJ

Now we have to calculate the enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat gained = 2.242 kJ

n = number of moles fructose = \frac{\text{Mass of manganese}}{\text{Molar mass of manganese}}=\frac{0.620 g}{54.94 g/mol}=0.0113 mol

\Delta H=-\frac{2.242 kJ}{0.0113 mol }=-199. kJ/mol

Therefore, the enthalpy change during the reaction is -199. kJ/mol.

8 0
3 years ago
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