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3 years ago

PHMWMHWPTYSM(19 points) ok last question tbh I’m a 90 old man jk lolololololololololololol

Chemistry

1 answer:

4vir4ik [10]3 years ago

6 0

Explanation:

the answer is circle 3 hope it helps

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Answer:

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3 years ago

If you remove two protons and two neutrons from a gold atom (au), what new element is formed (if any)?

ivanzaharov [21]

Answer: Iridium

Explanation:

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2 years ago

An atom of sulfur is represented by 3316s. how many neutrons are in the nucleus of this atom?express your answer as an integer.

user100 [1]

In this question, the sulfur atom has atomic number 16 and atomic mass 33. The Atomic number represents the number of the proton inside the atoms and atomic mass represent the mass of the atoms. Since electron mass to small, the atomic mass can be interpreted as the sum of neutron and proton. Then, the number of the neutron would be:

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3 years ago

What is the most accurate description of c6h12o6?

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3 years ago

What mass (g) of magnesium nitride (Mg3N2) can be made from the reaction of 1.22 g of magnesium with excess nitrogen? __Mg + __N

Citrus2011 [14]

<h3>Answer:</h3>

1.69 g Mg₃N₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis
Reactions RxN

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] Mg + N₂ → Mg₃N₂

[RxN - Balanced] 3Mg + N₂ → Mg₃N₂

[Given] 1.22 g Mg

[Solve] grams Mg₃N₂

<u>Step 2: Identify Conversions</u>

[RxN] 3 mol Mg → Mg₃N₂

[PT] Molar Mass of Mg - 24.31 g/mol

[PT] Molar Mass of N - 14.01 g/mol

Molar Mass of Mg₃N₂ - 3(24.31) + 2(14.01) = 100.95 g/mol

<u>Step 3: Stoich</u>

[DA] Set up: $\displaystyle 1.22 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg})(\frac{1 \ mol \ Mg_3N_2}{3 \ mol \ Mg})(\frac{100.95 \ g \ Mg_3N_2}{1 \ mol\ Mg_3N_2})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 1.68873 \ g \ Mg_3N_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.68873 g Mg₃N₂ ≈ 1.69 g Mg₃N₂

8 0

3 years ago