H - 1.01
C - 12.01
0 - 16.00
2(1.01) + 12.01 + 2(16.00) = 46.03 g/mol
<span>Determining the number chloride molecules that will result from this reaction requires we first determine the number of moles of arsenic and the number of moles of chlorine on hand.
1.587 grams of arsenic divided by its atomic weight of 74.92 grams per mole results in 0.0212 moles.
We do the same for chlorine. 2.755 grams of chlorine divided by 35.45 grams per mole gives us 0.106 moles.
0.106 moles divided by .0212 moles equals 5; therefore, the simplest formula of the chloride produced will be AsCl</span>₅<span>.</span>
The correct answer to this question is letter "B) 8.4 × 10-4 M."
2CO+O2<->2CO2
-x -x +x
It started as 2CO2 so +x, then it decomposed into 2CO and O2, so-x
2CO-oxidized, O2-Oxidized, 2CO2-reduced
the easiest way is to look at the equation, so if we have some reactant and no product
A<->2C+D
-x +2x +x
so if we had product concentration, and no reactant concentration
3A<-> C+D
+3x -x-x
<span>
</span>
Answer:
D. Oxidation
Explanation:
In an <em>electrolytic cell</em>, oxidation (the loss of electrons) takes place at the anode. At the cathode reduction takes place.
A mnemonic technique that could be used is that the process that starts with a vowel (Oxidation) takes place at the place that also starts with a vowel (Anode).
