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aev [14]
3 years ago
7

Give the names of the elements combined in barium sulfide.

Chemistry
1 answer:
Kryger [21]3 years ago
8 0

Answer:

Barium and sulpher are the elements that forms barium sulphide .

And its molecular fomula is BaS.

Explanation:

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What volume is equivalent to 12.0 m^3?
anzhelika [568]

1.2 x 10^10 mm^3 is equivalent to 12.0 m^3

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A geological process changes the weather. the Earth’s surface. the Earth’s core . nothing
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A geological process changes the Earth's surface.
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An object has a mass of 18.4g and a volume of 11.2 ml what is the density
DENIUS [597]

Density=mass/volume

Density=18.4g/11.2ml

Density=1.64

Just make sure you include the unit of measurement with your answer.

4 0
4 years ago
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If a strong base, like NaOH, is added to a strong acid, like HCl, the pH of the resultant solution will _________. A.) Go up B.)
MakcuM [25]

Answer:

B.) Go down

Explanation:

Hello,

In this case, a strong base like NaOH has a high pH based on the scale wherein 7 is neutral, above 7 is basic and below 7 is acid. In such a way, by adding an acid, having a low pH, once it is added, the pH will go down until the equivalence point, which for strong base and strong acid should be 7.

Best regards.

7 0
4 years ago
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formic acid, hcooh, is a weak acid with a ka equal to 1.8×10–4. what is the ph of a 0.0115 m aqueous formic acid solution?
kvasek [131]

The pH of a 0.0115 m aqueous formic acid solution is  mathematically given as

pH=2.8424

This is further explained below.

<h3>What is the ph of a 0.0115 m aqueous formic acid solution?</h3>

Generally,   the equation for the chemical equation is  mathematically given as

HCOOH   H^+ + HCOO

\quad C-C \alpha \quad C \alpha

&k a=\frac{c^2 \alpha^2}{e(1-\alpha)}\\\\&K_a=\frac{c \alpha^2}{1-\alpha_4} \quad|\gg\rangle \alpha\\\\&K_a=c \alpha^2\\\\&\alpha=\sqrt{\frac{k a}{c}}\\\\&\alpha=\sqrt{\frac{1.8 \times 10^{-4}}{0.0115}}\\\\&\alpha=\sqrt{156: 527710^{-4}}\\\\&\alpha=\sqrt{1.565 \times 1 \sigma^2}\\\\&\alpha=1.25 \times 10^{-1}\\\\&\alpha=0.125\\

&\left[\mathrm{H}^{+}\right]=\mathrm{C \alpha}\\\\&=0.125 \times 0.0115\\\\&=1.4375 \times 10^{-9}\\\\&P=-\log \left[H^{+}\right]\\\\&=-\log \left[1.4375 \times 10^{-3}\right]\\\\&P H=2.8424

Read more about  chemical equation

brainly.com/question/28294176

#SPJ1

8 0
1 year ago
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