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Tcecarenko [31]
4 years ago
8

What is a creative title for dry ice boo bubbles project?

Chemistry
2 answers:
Snezhnost [94]4 years ago
8 0
Dry bubbles(sorry I'm not good at titles)
DerKrebs [107]4 years ago
7 0
BBdrice!! LOLOLOL i think its weird but creative
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The mass percent of Cl⁻ in a seawater sample is determined by titrating 25.00 mL of seawater with AgNO₃ solution, causing a prec
Serga [27]

Answer:

2.5 %

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For AgNO_3 :

Molarity = 0.2850 M

Volume = 63.30 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 63.30 × 10⁻³ L

Thus, moles of AgNO_3 :

Moles=0.2850 \times {63.30\times 10^{-3}}\ moles

Moles of AgNO_3  = 0.0180405 moles

Moles of AgNO_3  = Moles of Cl^-

Thus, Moles of Cl^- = 0.0180405 moles

Molar mass of Cl^- = 35.453 g/mol

Mass = Moles * Molar mass = 0.0180405 moles * 35.453 g/mol = 0.6396 g

Volume of sea water = 25.00 mL

Density = 1.024 g/mL

Density = Mass / Volume

Mass = Density * Volume = 1.024 g/mL * 25.00 mL = 25.6 g

Mass\ \%=\frac{Mass_{Chloride ion}}{Total\ mass}\times 100

Mass\ \%=\frac{0.6396}{25.6}\times 100

<u>Mass percent of Cl⁻ = 2.5 %</u>

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